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Rina8888 [55]
3 years ago
6

Whoever is good at physics, can you help me with these questions?

Physics
2 answers:
qwelly [4]3 years ago
5 0

Answer:

i honestly do not know the awnser , im just setting up my brainly account

Anna [14]3 years ago
5 0

Answer:

Q)32) What is the unit of intensity of sound

Ans)Decibel

Q)33) Relate amplitude and distance to the intensity and loudness of sound

Ans)The average amount of energy passing through a unit area per unit of time in a specified direction is called the intensity of the wave. As the amplitude of the sound wave increases, the intensity of the sound increases. (i can't find the answer for distance and loudness i can't find it on g....o...o....g....l.....e and my textbook u will have to search it on ur own sorry)

Q)34) What is the pitch of sound

Pitch is the rise and fall of our voice when we speak. It is the characteristic of sound by which we can distinguish the sounds of the same loudness. Types: Pitch is generally of two types, high pitch and low pitch. High Pitch: The higher the frequency of the sound, the higher will be the pitch.

Q)35) How is pitch of sound related to its frequency of sound waves?

The sensation of a frequency is commonly referred to as the pitch of a sound. The pitch of the sound we hear depends on the frequency of the sound wave. A high frequency sound wave has a high pitch, and a low frequency sound has a low pitch.

Q)36) Define the Doppler effect?

The apparent change in the frequency of sound due to the relative motion between the source and the observer is called the Doppler effect.

Q)37) Explain why the doppler effect occurs

The Doppler effect, or Doppler shift, occurs when the movement of an observer relative to a source (or vice versa) causes a change in wavelength or frequency.

Sorry i can't find the last one i will try to search it afterwards

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A treasure chest full of silver and gold coins is being lifted from a pirate ship to the shore using two ropes as shown in the f
stiks02 [169]

The tension in rope C is determined as 122.23 N.

<h3>Tension in rope C</h3>

The tension in rope C is calculated as follows;

B² = A² + C²

C² = B² - A²

C² = (752²) - (742²)

C² = 14,940

C = √14,940

C = 122.23 N

Thus, the tension in rope C is determined as 122.23 N.

Learn more about tension here: brainly.com/question/24994188

#SPJ1

7 0
2 years ago
What universal standard is the basis of the atomic mass unit
ki77a [65]
<span>The mass of Avogadro's number of Carbon-12 atoms, which exactly equals 12.000</span>
4 0
3 years ago
Read 2 more answers
A belief, judgment, or way of thinking about something is called a(n) __________.
NISA [10]
That is an opinion. Opinion is not fact, although it can be based upon fact.
8 0
3 years ago
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1.How far is Object Z from the origin at t = 3 seconds?
GenaCL600 [577]

Answer:

Please find the answer in the explanation

Explanation:

1.) How far is Object Z from the origin at t = 3 seconds

The distance of the object Z from the origin will be the slope of the graph.

Slope = 4/2 = 2m

2.) Which object takes the least time to reach a position 4 meters from the origin ?

According to the graph given to the question above, object Z has the list time which is 2 seconds since object X does not start from the origin.

3.) Which object is farthest from the origin at t = 2 seconds?

The correct answer is still object Z because it has the highest slope.

4 0
3 years ago
A toy rocket, launched from the ground, rises vertically with an acceleration of 28 m/s 2 for 9.7 s until its motor stops. Disre
vredina [299]

Answer:

5080.86m

Explanation:

We will divide the problem in parts 1 and 2, and write the equation of accelerated motion with those numbers, taking the upwards direction as positive. For the first part, we have:

y_1=y_{01}+v_{01}t+\frac{a_1t^2}{2}

v_1=v_{01}+a_1t

We must consider that it's launched from the ground (y_{01}=0m) and from rest (v_{01}=0m/s), with an upwards acceleration a_{1}=28m/s^2 that lasts a time t=9.7s.

We calculate then the height achieved in part 1:

y_1=(0m)+(0m/s)t+\frac{(28m/s^2)(9.7s)^2}{2}=1317.26m

And the velocity achieved in part 1:

v_1=(0m/s)+(28m/s^2)(9.7s)=271.6m/s

We do the same for part 2, but now we must consider that the initial height is the one achieved in part 1 (y_{02}=1317.26m) and its initial velocity is the one achieved in part 1 (v_{02}=271.6m/s), now in free fall, which means with a downwards acceleration a_{2}=-9,8m/s^2. For the data we have it's faster to use the formula v_f^2=v_0^2+2ad, where d will be the displacement, or difference between maximum height and starting height of part 2, and the final velocity at maximum height we know must be 0m/s, so we have:

v_{02}^2+2a_2(y_2-y_{02})=v_2^2=0m/s

Then, to get y_2, we do:

2a_2(y_2-y_{02})=-v_{02}^2

y_2-y_{02}=-\frac{v_{02}^2}{2a_2}

y_2=y_{02}-\frac{v_{02}^2}{2a_2}

And we substitute the values:

y_2=y_{02}-\frac{v_{02}^2}{2a_2}=(1317.26m)-\frac{(271.6m/s)^2}{2(-9.8m/s^2)}=5080.86m

3 0
3 years ago
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