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Rina8888 [55]
3 years ago
6

Whoever is good at physics, can you help me with these questions?

Physics
2 answers:
qwelly [4]3 years ago
5 0

Answer:

i honestly do not know the awnser , im just setting up my brainly account

Anna [14]3 years ago
5 0

Answer:

Q)32) What is the unit of intensity of sound

Ans)Decibel

Q)33) Relate amplitude and distance to the intensity and loudness of sound

Ans)The average amount of energy passing through a unit area per unit of time in a specified direction is called the intensity of the wave. As the amplitude of the sound wave increases, the intensity of the sound increases. (i can't find the answer for distance and loudness i can't find it on g....o...o....g....l.....e and my textbook u will have to search it on ur own sorry)

Q)34) What is the pitch of sound

Pitch is the rise and fall of our voice when we speak. It is the characteristic of sound by which we can distinguish the sounds of the same loudness. Types: Pitch is generally of two types, high pitch and low pitch. High Pitch: The higher the frequency of the sound, the higher will be the pitch.

Q)35) How is pitch of sound related to its frequency of sound waves?

The sensation of a frequency is commonly referred to as the pitch of a sound. The pitch of the sound we hear depends on the frequency of the sound wave. A high frequency sound wave has a high pitch, and a low frequency sound has a low pitch.

Q)36) Define the Doppler effect?

The apparent change in the frequency of sound due to the relative motion between the source and the observer is called the Doppler effect.

Q)37) Explain why the doppler effect occurs

The Doppler effect, or Doppler shift, occurs when the movement of an observer relative to a source (or vice versa) causes a change in wavelength or frequency.

Sorry i can't find the last one i will try to search it afterwards

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<span>0.5 . k . x^2 = 0.5 . m . v^2 = m . g . ∆h </span>

<span>0.5 . 50 . (0.1^2) = 0.05 . 9.8 . ∆h </span>

<span>∆h = 0.51 m = 51 cm </span>

<span>This is the height gained </span>
<span>Distance along the slope = ∆h / sin 60 = 0.589 = 59 cm </span>

<span>In the second case, the stored spring energy is converted into height energy AND frictional heat energy. </span>

<span>The height energy is m . g . d sin 60 where d is the distance the cube moves along the slope. </span>

<span>The Frictional energy converted is F . d </span>

<span>F ( the frictional force ) = µ . N </span>

<span>N ( the reaction to the component of the gravity force perpendicular to the surface of the slope ) = m . g . cos60 </span>

<span>Total energy converted </span>

<span>0.5 . k . x^2 = (m . g . dsin60) + (µ . m . g . cos60 . d ) </span>

<span>Solve for d </span>

<span>d = 0.528 = 53 cm</span>
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