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3 years ago

How planes stay in the air? PLEASE HELP!!!

1 answer:

5 0

Planes stay in the air by a force called lift which is gained as a plane rises in the air as air goes under the plane a force called lift is applied because hot air rises so the hot air also pushes the plane goes up.
hope this helps :3

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If liquid water is exposed to normal atmospheric pressure, what needs to change in order to change its state of matter?

inn [45]

Answer: Option (b) is the correct answer.

Explanation:

State of a substance changes when heat is provided to a substance.

This is because when we heat water then intermoleclar forces present within its molecules tend to break down. Due to this molecules start to move away from each other.

As a result, kinetic energy of molecules increases and they collide rapidly. Hence, solid state of water changes into liquid state and upon excessive heating liquid state of water changes into vapor state.

Thus, we conclude that temperature of water needs to change in order to change its state of matter.

6 0

3 years ago

Read 2 more answers

Convert 6.7 x 1024 molecules of nitrogen dioxide into grams.

BlackZzzverrR [31]

Answer:

510 g NO₂

General Formulas and Concepts:

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Reading the Periodic Table
Writing Compounds
Using Dimensional Analysis

Explanation:

Step 1: Define

6.7 × 10²⁴ molecules NO₂ (Nitrogen dioxide)

Step 2: Define conversions

Avogadro's Number

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of NO₂ - 14.01 + 2(16.00) = 46.01 g/mol

Step 3: Use Dimensional Analysis

$6.7 \cdot 10^{24} \ molecules \ NO_2(\frac{1 \ mol \ NO_2}{6.022 \cdot 10^{23} \ molecules \ NO_2} )(\frac{46.01 \ g \ NO_2}{1 \ mol \ NO_2} )$ = 511.901 g NO₂

Step 4: Check

We are given 2 sig figs. Follow sig fig rules.

511.901 g NO₂ ≈ 510 g NO₂

6 0

3 years ago

What volume of 0.152 M KMnO4 solution would completely react with 20.0 mL of 0.381 M FeSO4 solution according to the following n

ANEK [815]

Answer: The volume of permanganate ion (potassium permanganate) is 10.0 mL

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of ferrous sulfate solution = 0.381 M

Volume of solution = 20.0 mL = 0.020 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.381M=\frac{\text{Moles of ferrous sulfate}}{0.020L}\\\\\text{Moles of ferrous sulfate}=(0.381mol/L\times 0.020L)=0.00762mol$

For the given chemical equation:

$5Fe^{2+}+8H^++MnO_4^-\rightarrow 5Fe^{3+}+Mn^{2+}+4H_2O$

By Stoichiometry of the reaction:

5 moles of iron (II) ions (ferrous sulfate) reacts with 1 mole of permanganate ion (potassium permanganate)

So, 0.00762 moles of iron (II) ions (ferrous sulfate) will react with = $\frac{1}{5}\times 0.00762=0.00152mol$ of permanganate ion (potassium permanganate)

Now, calculating the volume of permanganate ion (potassium permanganate) by using equation 1, we get:

Molarity of permanganate ion (potassium permanganate) = 0.152 M

Moles of permanganate ion (potassium permanganate) = 0.00152 mol

Putting values in equation 1, we get:

$0.152mol/L=\frac{0.00152mol}{\text{Volume of permanganate ion (potassium permanganate)}}\\\\\text{Volume of permanganate ion (potassium permanganate)}=\frac{0.00152mol}{0.152mol/L}=0.01L=10.0mL$

Hence, the volume of permanganate ion (potassium permanganate) is 10.0 mL

3 0

3 years ago

A scooter maintains a pace of 1.45 minutes per mile, with fuel economy of 85 miles per gallon. How many seconds can it travel on

vlada-n [284]

Answer:

281s

Explanation:

Given parameters:

Speed of the scooter = 1.45min per mile

Fuel economy of engine = 85miles per gallon

Quantity of fuel = 145mL

Unknown:

Time of travel with the volume of fuel given = ?

Solution:

To solve this problem, we need to find the distance the fuel will last.

Rate of fuel consumption by the engine = 85miles per gallon

Convert 145mL to gallons;

3785.41mL = 1 gallon

145mL will therefore give $\frac{145}{3785.41}$ = 0.038gallons

So;

Distance covered = 85miles per gallon x 0.038gallons = 3.23miles

From;

Rate of travel = $\frac{time }{distance}$

Time = rate of travel x distance = 1.45 minutes per mile x 3.23miles

Time = 4.7min

1 min = 60s

4.7min = 4.7 x 60 = 281s

6 0

3 years ago

0.20dm

Alex_Xolod [135]

Answer:

I don't no sorry. ਕਿਉੁਂਕਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ ਸਤਿ 478figxigxurRyyv ਸ੍

5 0

3 years ago