Chemical ; Conducts heat and electricity, Reacts with dilute acids.
Physical : Ductile and Malleable.
Answer:
Empirical formula of 81.8 carbon and 18.2 hydrogen
Steps
- Find the empirical formula of a compound that has 81.8% of Carbon (C), 18.2% of Hydrogen (H).
- Divide by fractional component of each mole value: C=1.5354936431103, H=4.0709872862205Round to closest whole numbers: C=2, H=4
<h3> Combine to get the empirical formula: C2H4</h3>
Answer:
The molarity of this KOH solutions 3.21 mol / L (option C is correct)
Explanation:
Step 1: Data given
Mass of KOH = 45.0 grams
Molar mass of KOH = 56.1 g/mol
Volume = 250.0 mL = 0.250 L
Step 2: Calculate moles KOH
Moles KOH = mass KOH / molar mass KOH
Moles KOH = 45.0 grams / 56.1 g/mol
Moles KOH = 0.802 moles
Step 3: Calculate molarity
Molarity KOH solution = moles KOH / volume water
Molarity KOH solution = 0.802 moles / 0.250 L
Molarity KOH solution = 3.21 mol / L
The molarity of this KOH solutions 3.21 mol / L (option C is correct)
Answer: Lysosomes
Explanation: The lysosome is an organelle that contains digestive enzymes and acts as the organelle-recycling facility of an animal cell. It breaks down old and unnecessary structures so their molecules can be reused. Lysosomes are part of the endomembrane system, and some vesicles that leave the Golgi are bound for the lysosome.