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3 years ago

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Physics

2 answers:

neonofarm [45]3 years ago

7 0

Answer:

Ok wait I'll subscribe now

Explanation:

make me brainlatest Thanks

g100num [7]3 years ago

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Answer:

make hgoniabo brainliest coz i don't subs u :(

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A 68.2 kg base runner begins his slide into second base while moving at a speed of 4.33 m/s. He slides so that his speed is zero

qwelly [4]

Answer:

$147.653J = W_f$

Explanation:

We know that:

$E_i - E_f = W_f$

where $E_i$ is the initial energy, $E_f$ is the final energy and $W_f$ is the energy lost due to friction.

so:

$\frac{1}{2}MV^2-0 = W_f$

Where M is the mass and V is the velocity of the runner, so:

$\frac{1}{2}(68.2kg)(4.33m/s)^2 = W_f$

$147.653J = W_f$

7 0

4 years ago

In this lab, you will use a dynamics track to generate collisions between two carts. If momentum is conserved, what variable cha

BartSMP [9]

In collision type of problems since momentum is always conserved

we can say

$m_1v_{1i} + m_2v_{2i} = m_1 v_{1f} + m_2v_{2f}$

So here along with this equation we also required one more equation for the restitution coefficient

$v_{2f} - v_{1f} = e(v_{1i} - v_{2i})$

so above two equations are required to find the velocity after collision

here the change in velocity occurs due to the contact force while they contact in each other

so this is the impulse of collision while they are in contact with each other while in collision which changes the velocity of two colliding objects

8 0

4 years ago

Read 2 more answers

To aid in the prevention of tooth decay, it is recommended that drinking water contain 0.800 ppm fluoride, F−. How many grams of

Leviafan [203]

Answer:

2.23 × 10^6 g of F- must be added to the cylindrical reservoir in order to obtain a drinking water with a concentration of 0.8ppm of F-

Explanation:

Here are the steps of how to arrive at the answer:

The volume of a cylinder = ((pi)D²/4) × H

Where D = diameter of the cylindrical reservoir = 2.02 × 10^2m

H = Height of the reservoir = 87.32m

Therefore volume of cylindrical reservoir = (3.142×202²/4)m² × 87.32m = 2798740.647m³

1ppm = 1g/m³

0.8ppm = 0.8 × 1g/m³

= 0.8g/m³

Therefore to obtain drinking water of concentration 0.8g/m³ in a reservoir of volume 2798740.647m³, F- of mass = 0.8g/m³ × 2798740.647m³ = 2.23 × 10^6 g must be added to the tank.

Thank you for reading.

4 0

3 years ago

A uniform rod of mass M and length L is free to swing back and forth by pivoting a distance x from its center. It undergoes harm

Alisiya [41]

Answer:

The moment of inertia is 0.7500 kg-m².

Explanation:

Given that,

Mass = 2.2 kg

Distance = 0.49 m

If the length is 1.1 m

We need to calculate the moment of inertia

Using formula of moment of inertia

$I=\dfrac{1}{12}ml^2+mx^2$

Where, m = mass of rod

l = length of rod

x = distance from its center

Put the value into the formula

$I=\dfrac{1}{12}\times2.2\times(1.1)^2+2.2\times(0.49)^2$

$I=0.7500\ kg-m^2$

Hence, The moment of inertia is 0.7500 kg-m².

5 0

3 years ago

If the air starts at a pressure of 1.0 atm, and you hold the volume of your lungs constant (a good approximation) and the number

Misha Larkins [42]

Answer:

the question is incomplete, here is the complete question.

"On a chilly 12∘C day, you quickly take a deep breath--all your lungs can hold, 4.0 L. The air warms to your body temperature of 37∘C.If the air starts at a pressure of 1.0 atm, and you hold the volume of your lungs constant (a good approximation) and the number of molecules in your lungs stays constant as well (also a good approximation), what is the increase in pressure inside your lungs?

1.09 atm

Explanation:

the question addresses an ideal gas. where the relationship between the volume(v),pressure(p),temperature(T) and nos of molecules(n) is expressed as

$PV=nRT\\$