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Sophie [7]
3 years ago
10

If a 2 kg ball is at the edge of a 40 meter cliff and falls off, how much kinetic energy will the ball have when it hits the gro

und?
Physics
1 answer:
Nutka1998 [239]3 years ago
3 0

m = mass of the ball at the edge of the cliff = 2 kg

h = height of the cliff from where the ball falls off = 40 m

g = acceleration due to gravity = 9.8 m/s²

gravitational potential energy of the ball at the top of the cliff is given as

PE = mgh

inserting the above values in the formula

PE = (2) (9.8) (40)

PE = 784 J

KE = kinetic energy of the ball as hits the ground.

initially at the top of cliff , the ball has no kinetic energy and only potential energy. as the ball falls down the cliff , the speed of ball increase which increases the kinetic energy and potential energy decrease by same amount as the height above the ground decrease.

using conservation of energy

kinetic energy of ball as it hits the ground = Potential energy of the ball at the top of cliff

KE = PE

KE = 784 J

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A train has an initial velocity of 44m/s and an accelaration of _4m/s calculate its velocity​
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Complete question:

A train has an initial velocity of 44m/s and an acceleration of -4m/s². calculate its velocity​ after 10s ?

Answer:

the final velocity of the train is 4 m/s.

Explanation:

Given;

initial velocity of the train, u = 44 m/s

acceleration of the train, a = -4m/s² (the negative sign shows that the train is decelerating)

time of motion, t = 10 s

let the final velocity of the train = v

The final velocity of the train is calculated using the following kinematic equation;

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v = 44 - 40

v = 4 m/s

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The acceleration of an object is a measure of how its speed changes over time.

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Then

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