The mass of the (elevator + person) is (2,000 kg + 60 kg) = 2,060 kg .
The weight is (mass x gravity) = (2,060 x 10) = 20,600 newtons
Work = (force x distance) = (20,600 newtons x 24m) = <em>494,400 joules</em>
The speed, acceleration, and how much time it takes don't make any
difference, unless you want the average power during the lift.
Power = (work)/(time) =
494,000 J / (24/4 m) =
494,000 J / 6 sec = <em><u>82,400 watts</u></em> wow !
horizontal distance of home run is 400 ft = 122 m
height of the home run is 3 ft = 0.9 m
now the angle of the hit is 51 degree
now we have equation of trajectory of the motion


solving above two equations we have

now here we will plug in all data




<em>so the ball was hit with speed 35.1 m/s from the ground</em>
Answer:
The stress is calculated as 
Solution:
As per the question:
Length of the wire, l = 75.2 cm = 0.752 m
Diameter of the circular cross-section, d = 0.560 mm = 
Mass of the weight attached, m = 25.2 kg
Elongation in the wire, 
Now,
The stress in the wire is given by:
(1)
Now,
Force is due to the weight of the attached weight:
F = mg = 
Cross sectional Area, A = 
Using these values in eqn (1):