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guapka [62]
3 years ago
11

How much energy to be removed to drop the temperature of 5.7kg of wood from 20degrees to 7degrees. #100points

Physics
2 answers:
Neporo4naja [7]3 years ago
5 0

see i was trying to figure out the answer but i didn't understand it so i took the time to research and work it out but i still didn't understand i found one that was close to it and i got the same one as the other person which is D but idk if it is that type of question if it is than it is d if not then idk

WITCHER [35]3 years ago
5 0

Answer:

D is correct they were correct

Explanation:

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Zarrin [17]
It’s coming in contact with more air molecules than I would if it was in a ball because there is less surface area
4 0
3 years ago
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Does anybody know how to answer any of these questions? Any of them without a check mark.
aivan3 [116]

Explanation:

sorry I can't help u right now

3 0
3 years ago
A 1.53-kg bucket hangs on a rope wrapped around a pulley of mass 7.07 kg and radius 66 cm. This pulley is frictionless in its ax
levacccp [35]

Answer:

\alpha = 6.431\,\frac{rad}{s^{2}}

Explanation:

The pulley is modelled by the Newton's Laws, whose equation of equilibrium is:

\Sigma M = T \cdot R = \frac{1}{2}\cdot M \cdot R^{2}\cdot \alpha

Given that tension is equal to the weight of the bucket, the angular acceleration experimented by the pulley is:

T = \frac{1}{2}\cdot M \cdot R \cdot \alpha

m_{b}\cdot g = \frac{1}{2}\cdot M \cdot R \cdot \alpha

\alpha = \frac{2\cdot m_{b}\cdot g}{M\cdot R}

\alpha = \frac{2\cdot (1.53\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{(7.07\,kg)\cdot (0.66\,m)}

\alpha = 6.431\,\frac{rad}{s^{2}}

7 0
3 years ago
An electron has a charge of 1.602 X 10-19.coulomb. When two electrons are separated by 1.2 X 10-9m, what force will they exert o
amid [387]

Answer:

The force they will exert on each other is 1.6*10⁻¹⁰ N

Explanation:

The electromagnetic force is the interaction that occurs between bodies that have an electric charge. When the charges are at rest, the interaction between them is called the electrostatic force. Depending on the sign of the interacting charges, the electrostatic force can be attractive or repulsive. The electrostatic interaction between charges of the same sign is repulsive, while the interaction between charges of the opposite sign is attractive.

Coulomb's law is used to calculate the electric force acting between two charges at rest. This force depends on the distance "r" between the electrons and the charge of both.

Coulomb's law is represented by:

F=k*\frac{q1*q2}{r^{2} }

where:

  • F = electric force of attraction or repulsion in Newtons (N). Like charges repel and opposite charges attract.
  • k = is the Coulomb constant or electrical constant of proportionality.
  • q = value of the electric charges measured in Coulomb (C).
  • r = distance that separates the charges and that is measured in meters (m).

In this case:

  • k= 9*10⁹ \frac{N*m^{2} }{C^{2} }
  • q1= 1.602*10⁻¹⁹ C
  • q2= 1.602*10⁻¹⁹ C
  • r= 1.2*10⁻⁹ m

Replacing:

F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{1.602*10^{-19} C*1.602*10^{-19} C}{(1.2*10^{-9} )^{2} }

and solving you get:

F=1.6*10⁻¹⁰ N

<u><em>The force they will exert on each other is 1.6*10⁻¹⁰ N</em></u>

3 0
3 years ago
In a two planet system, does an increase in planet velocity result in a decreased period?
olganol [36]
From the formula,
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V(velocity is inversely related to T),so when v increases then time period will decrease.
Option a is correct.
5 0
3 years ago
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