1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
snow_tiger [21]
3 years ago
9

Cobalt (Co) has an atomic mass of 59 and an atomic number of 27. Which statement correctly describes an atom of cobalt?

Physics
1 answer:
kifflom [539]3 years ago
8 0

Answer:

Option A. An atom of cobalt contains more neutrons than protons.

Explanation:

From the question given above, the following data were obtained:

Mass number = 59

Atomic number = 27

Next, we shall determine the number of protons in the atom. This is illustrated below:

Atomic number of an element is simply defined as the number of protons in the atom of the element. Thus,

Atomic number = proton number

Atomic number = 27

Therefore,

Proton number = 27

Next, we shall determine the neutron number. This can be obtained as follow:

Mass number = 59

Proton number = 27

Neutron number =?

Mass number = Proton + Neutron

59 = 27 + Neutron

Collect like terms

Neutron = 59 – 27

Neutron number = 32

Next, we shall determine the number of electrons. This can be obtained as follow:

Since the atom is neutral i.e it has no charge, then, the number of protons and electrons are equal. Thus,

Electron number = Proton number

Proton number = 27

Therefore,

Electron number = 27

Summary:

Mass number = 59

Atomic number = 27

Proton number = 27

Neutron number = 32

Electron number = 27

From the above, we can see that the atom of cobalt contains:

1. More neutrons than protons.

2. The same number of protons and electrons.

Therefore, option A gives the correct answer to the question.

You might be interested in
A(n) 9.9 g bullet is fired into a(n) 138 g block of wood at rest on a horizontal surface and stays inside. After impact, the blo
kompoz [17]

Answer:

185.25 m/s

Explanation:

consider the motion of the combination of bullet and block after the collision

v₀ = initial speed just after the collision

v' = final speed = 0 m/s

μ = Coefficient of friction = 0.6

g = acceleration due to gravity = 9.8 m/s²

a = acceleration of the combination = - μ g = - (0.6) (9.8) = - 5.88 m/s²

d = stopping distance = 13 m

using the kinematics equation

v'² = v₀² + 2 a d

0² = v₀² + 2 (- 5.88) (13)

v₀ = 12.4 m/s

m = mass of the bullet = 9.9 g = 0.0099 kg

M = mass of the wood = 138 g = 0.138 kg

v = speed of bullet before collision

v₀ = speed of combination after the collision = 12.4 m/s

Using conservation of momentum

m v = (m + M) v₀

(0.0099) v = (0.0099 + 0.138) (12.4)

v = 185.25 m/s

3 0
3 years ago
Calculate the force on an object with mass of 50kg and gravity of 10​
GarryVolchara [31]
Answer: 500 N

Explanation:

The formula to find the force exerted by a mass, we may use F = mg, where g, the gravity, and a, the acceleration, can be interchangeable in the formula.

1) F = 50 x 10
2) F = 500 N

Hope this helps, brainliest would be appreciated :)
6 0
3 years ago
A 2:2 kg toy train is con ned to roll along a straight, frictionless track parallel to the x-axis. The train starts at the origi
Liula [17]

Answer:

a) 10.51 J

b) 3.48 m/s

Explanation:

Given data :

mass of train ( M ) = 2.2 kg

Given initial velocity ( u ) = 1.6 m/s

<u>a) calculating work done by the force over the journey of the train</u>

F = mx + b  ------ ( 1 )

m = slope  = ( Δ f / Δ x ) = 2.8 / -7.5 = - 0.373 N/m

x = distance travelled on the x axis by the train = 7.5 m

F = force experienced by the train = 2.8 N

x = 0

∴ b = 2.8

hence equation 1 can be written as

F = ( -0.373) x + 2.8   ----- ( 2 )

hence to determine the work done by the force

W   = \int\limits^7_0 { ( -0.373) x + 2.8  )} \, dx     Note:  the limits are actually 7.5 and 0

∴ W ( work done ) = -10.49 + 21 = 10.51 J

<u>b) calculate the speed of the train at the end of its journey</u>

we will apply the work energy theorem

W = 1/2 m*v^2  -  1/2 m*u^2

∴ V^2 = 2 / M ( W + 1/2 M*u^2 )  ( input values into equation )

 V^2 = 12.11

hence V = 3.48 m/s

6 0
3 years ago
Which example best illustrates that light behaves like particles?
AlekseyPX
I would say B. Because actual mass would ricochet off the sidewalk.
8 0
3 years ago
Read 2 more answers
A spring with constant k = 78 N/m is at the base of a frictionless, 30.0°-inclined plane. A 0.50-kg block is pressed against the
olasank [31]

Explanation:

The given data is as follows.

   Spring constant (k) = 78 N/m,     \theta = 30^{o}

 Mass of block (m) = 0.50 kg

According to the formula of energy conservation,

                mgh sin \theta = \frac{1}{2}kx^{2}

       h = \frac{1}{2} \times \frac{kx^{2}}{mg Sin \theta}

          = \frac{78 \times 0.04}{2 \times 0.5 \times 9.8 \times 0.5}

          = 0.64 m

Thus, we can conclude that the distance traveled by the block is 0.64 m.

4 0
3 years ago
Other questions:
  • A ski starts from rest and slides down a 22 incline 75 m long. if the coefficient of friction is 0.090, what is the ski's speed
    5·1 answer
  • Franz Mesmer believed that his ability to heal people was based on his manipulation of which force
    13·2 answers
  • A 12 kg bowling ball would require what force to accelerate down and alleyway at a rate of 3 m/s²?
    7·1 answer
  • Suppose we replace the original launcher with one that fires the ball upward at twice the speed. We make no other changes. How f
    6·1 answer
  • I really need help asap.
    10·2 answers
  • Conservation of Matter states that the reactants have to equal the _______. Answers products
    9·2 answers
  • A 104 horse-power suv speeds up from 21 m/s to 29 m/s in 3 seconds, what is the mass of the suv?
    9·1 answer
  • Time period of a simple pendulum is measured at karachi, what change will occur in the time period ,if it is measured on mount e
    10·1 answer
  • A circle is centered at C(0,0). The point M(0,38) is on the circle.
    14·1 answer
  • determine the longest wavelength of light required to remove an electron from a sample of potassium metal, if the binding energy
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!