All categories

3 years ago

What is the voltage between two short-circuited points? PLZ HELP ASAP

Physics

1 answer:

salantis [7]3 years ago

8 0

Answer

It states that V/I = R where V is potential difference R is resistance and I is the current flowing across the terminals.Now when short circuit the resistance ...

Explanation:

You might be interested in

6. A 4 kg object hangs below a 6 kg object by a string of negligible mass. If the 6 kg object is pulled upward by a force of 440

MrRissso [65]

Answer:

T =176 N

Explanation:

from diagram

F -(m_1+m_2_g) = (m_1+m_2_g)a

440 - (6+4)g = (6+4)a

a =\frac{440-10*9.8}{10}

a =34.2 m/s^2

frrom free body diagram of mass m2 = 4kg

T -m_2g =m_2a

T = m_2(g +a)

T = 4(9.81+34.2)

T =176 N

7 0

4 years ago

given the data 11.4, 11.3, 11.2 and 11.1 cm determine the average and its standard deviation using equation

Ostrovityanka [42]

Answer:

Average $\bar{x}$ = 11.25 cm

standard deviation = 0.129 cm

Explanation:

The data provided in the question is:

x₁ = 11.4 cm

x₂ = 11.3 cm

x₃ = 11.2 cm

x₄ = 11.1 cm

total number of data points, N = 4

Now, the average is calculated as:

Average $\bar{x}$ = $\frac{sum\ of\ all\ the\ data\ points }{number\ of\ data\ points}$

substituting the values in the above formula we get,

Average $\bar{x}$ = $\frac{11.4cm+11.3cm+11.2cm+11.1cm }{4}$

Average $\bar{x}$ = 11.25 cm

Now the standard deviation is calculated as:

standard deviation = $\sqrt\frac{\sum_{i=1}^{4} \left(x_i - \bar x \right )^2}{N-1}$

substituting the values in the above equation we get,

standard deviation = $\sqrt\frac{\left(11.4 - 11.25 \right )^2 + \left(11.3 - 11.25 \right )^2 + \left(11.2 - 11.25 \right )^2 + \left(11.1 - 11.25 \right )^2}{3}$

standard deviation = 0.129 cm

5 0

3 years ago

Can someone help me please? I’ve been trying to solve these questions all day.

qwelly [4]

#16

If we put a resistor in circuit it will slow the speed of current

Let's check ohms law

$\\ \rm\Rrightarrow \dfrac{V}{I}=R$

So if resistance is more current is less

#17

Again use ohms law

$\\ \rm\Rrightarrow V=IR$

$\\ \rm\Rrightarrow V\propto I$

Voltage must be increased

4 0

2 years ago

A lighter-than-air balloon and its load of passengers and ballast are floating stationary above the earth. ballast is weight (of

Natali5045456 [20]

Step 1: Find the upward acceleration.
d = 107 m
a = ???
vi = 0
t = 14.4 sec
d = vi * t + 1/2 at^2
107 = 1/2 a * 14.4^2
a = 214 / (14.4)^2
a = 1.03 m/s^2
Step 2: Find the Volume of the balloon and from that the mass.

V = 4/3 * pi * r^3
r = 6.52 m
V = 4/3 x pi x 6.52^3
V= 1,161 m^3.
Density of air = m/V 1.29 = m/ 1161
M = 1.29 x 1161
m = 1498 kg
Step 3: The force keeping this in equilibrium = F = m* g
F = 1498 * 9.81 = 14692 N
Step 4: Find the mass needed to cause the upward acceleration.
14692 = (1498 - x) * (9.81 + 1.03)
14692 = (1498 - x) * 10.84 Divide both sides by 10.84
1355.35 = 1022 - x
1355.35 - 1022
x = 333.35 kg

7 0

3 years ago

Calculate the acceleration of a bus whose speed changes from 6 m/s to 12 m/s over a period of 3s.

GenaCL600 [577]

Your answer would be 2.

8 0

4 years ago

What is the voltage between two short-circuited points? PLZ HELP ASAP​

What is the voltage between two short-circuited points? PLZ HELP ASAP