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3 years ago

On a planimetric map, the _____ is used to determine the actual distance between two points.

2 answers:

6 0

The answer in this question is scale. The scale is used to determine the actual distance between two points in a planimetric map. This map only represents the horizontal position of features. This is also called by others as the line map. This is usually consisted of man-made and natural features. These are from aerial shots by the use of modern technology. This map’s common features are street and water centerlines, sidewalks, culverts, utility lines, building footprints and vegetation. Sometimes, there are also other useful data attached in this map like titles of the properties, owner, assessed value, etc. It is because of these, this map becomes a storage of valuable data which can be easily and quickly accessed.

Karo-lina-s [1.5K]3 years ago

3 0

answer is scale-apex

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Which of the following BEST describes an object velocity during free fall?

Viefleur [7K]

Objects can only go so fast and that speed is called terminal velocity. so the answer is A

3 0

3 years ago

Light of wavelength 550 nm falls on a

Brums [2.3K]

Answer:

The first diffraction maximum fringe will be at approximately 2.7 meters from the central maximum.

Explanation:

We can describe single slit diffraction phenomenon with the equation:

$a\sin\theta=m\lambda$ (1)

with θ the angular position of the minimum of order m respect the central maximum, a the slit width and λ the wavelength of the incident light. Because the distances between the first minima and the central maximum ( $y_{m}$ ) are small compared to the distance between the screen and the slit (x), we can approximate $\sin\theta\approx\tan\theta=\frac{y}{x}$ , using this on (1):

$a\frac{y_{m}}{x}=m\lambda$

solving for y

$y_{m}= \frac{mx\lambda}{a}$

Note that $y_{m}$ is the distance between a minimum and the central maximum but we need the position of a maximum not a minimum, here we can use the fact that a maximum is approximately between two minima, so the first diffraction maximum fringe is between the minima of order 1 and 2, so we should find $y_{1}$ , $y_{2}$ add them and divide by two:

$y_{1}= \frac{(1)(10.0m)(550\times10^{-9}\,m)}{3.00\times10^{-6}\,m}$

$y_{1}= 1.8 m$

$y_{2}= \frac{(2)(10.0m)(550\times10^{-9}\,m)}{3.00\times10^{-6}\,m}$

$y_{1}= 3.6 m$

$maximum = \frac{1.8+3.6}{2}=2.7m$

7 0

3 years ago

A) Fill in the blanks in the following paragraph to correctly describe the nucleus of an atom.

nydimaria [60]

Answer:

Protons and Neutrons are the two types of nucleons that make up a nucleus. The electrostatic force exists between protons in the nucleus because of their charge. Because it is repulsive, this force tends to make a nucleus unstable. However, the strong nuclear force acts between protons, between neutrons, and between protons and neutrons. This force helps to make a nucleus stable, because it is always attractive.

Explanation:

The nucleus of an atom contains two types of particles, protons and neutrons. Proton has a positive charge, while neutron has no charge. The protons have a repulsive electrostatic force between each other, due to like charges. Due to this repulsive force protons tend to scatter away making the nucleus unstable. In order to overcome this, a force inside the nucleus binds these protons and neutrons together. This attractive force is called strong nuclear force. This force acts on very short ranges.

6 0

4 years ago

Read 2 more answers

~~~~NEED HELP ASAP~~~~

maksim [4K]

the above three pictures may help you

go through the attachments

4 0

3 years ago

Read 2 more answers

Gulls are often observed dropping clams and other shellfish from a height to the rocks below, as a means of opening the shells.

kumpel [21]

Answer:

v = 17.71 m / s

Explanation:

We can work this exercise with the kinematics equations. In general the body is released so that its initial velocity is zero, the acceleration of the acceleration of gravity

v² = v₀² - 2 g (y -y₀)

v² = 0 - 2g (y -y₀)

when it hits the stone the height is zero and part of the height of the seagull I

v² = 2g y₀

v = Ra (2g i)

let's calculate

v =√ (2 9.8 16)

v = 17.71 m / s

8 0

3 years ago