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4 years ago

14

On a planimetric map, the _____ is used to determine the actual distance between two points.

2 answers:

lawyer [7]4 years ago

6 0

<span>The answer in this question is scale. The scale is used to determine the actual distance between two points in a planimetric map. This map only represents the horizontal position of features. This is also called by others as the line map. This is usually consisted of man-made and natural features. These are from aerial shots by the use of modern technology. This map’s common features are street and water centerlines, sidewalks, culverts, utility lines, building footprints and vegetation. Sometimes, there are also other useful data attached in this map like titles of the properties, owner, assessed value, etc. It is because of these, this map becomes a storage of valuable data which can be easily and quickly accessed. </span>

Karo-lina-s [1.5K]4 years ago

3 0

answer is scale-apex

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Elements on the periodic table are ordered according to their _________

torisob [31]

Elements are arranged from left to right and top to bottom in order of increasing atomic number.:)

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3 years ago

Which three characteristics do mechanical waves and electrocmagnetic

elena-s [515]

Answer:

I think the correct answer is B.

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3 years ago

Read 2 more answers

A 74-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.56 m,

Reptile [31]

Answer:

Work done, W = 1.44 kJ

Explanation:

Given that,

Mass of boy, m = 74 kg

Initial speed of boy, u = 1.6 m/s

The boy then drops through a height of 1.56 m

Final speed of boy, v = 8.5 m/s

To find,

Non-conservative work was done on the boy.

Solution,

The work done by the non conservative forces is equal to the sum of total change in kinetic energy and total change in potential energy.

$W=\dfrac{1}{2}m(v^2-u^2)+(0-mgh)$

$W=\dfrac{1}{2}m(v^2-u^2)-mgh$

$W=\dfrac{1}{2}\times 74\times (8.5^2-1.6^2)-74\times 9.8\times 1.56$

W = 1447.21 Joules

or

W = 1.44 kJ

Therefore, the non conservative work done on the boy is 1.44 kJ.

4 0

3 years ago

I had gotten this one wrong please help thank you

Nata [24]

Check the 1st 2nd 3rd and 4th boxes

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4 years ago

(a) Calculate the number of free electrons per cubic meter for gold assuming that there are 1.5 free electrons per gold atom. Th

KonstantinChe [14]

Answer:

Part A:

$n=8.85*10^{28}m^{-3}$

Part B:

$Electron Mobility=3.03*10^{-3} m^2/V$

Explanation:

Part A:

To calculate the number of free electrons n we use the following formula::

n=1.5N-Au

Where N-Au is number of gold atoms per cubic meter

$N-Au=\frac{Density*Avogadro Number}{atomic weight}$

$Density = 19.32g/cm^3$

$Avogadro Number=6.02*10^{23} atoms/mol$

$Atomic weight=196.97g/mol$

So:

$n=1.5*\frac{Density*Avogadro Number}{atomic weight}$

$n=1.5*\frac{19.32*6.02*10^{23}}{196.97}$

$n=8.85*10^{28}m^{-3}$

Part B:

$Electron Mobility=\frac{Elec-conductivity}{n * charge on electron}$

n is calculated above which is 8.85*10^{28}m^{-3}

Charge on electron=1.602*10^{-19}

Elec- Conductivity= 4.3*10^{7}

$Electron Mobility=\frac{4.3*10^{7}}{ 8.85*10^{28} * 1.602*10^{-19}}$

$Electron Mobility=3.03*10^{-3} m^2/V$

4 0

4 years ago