In a force diagram set-up, we name the angle of inclination theta, g as the acceleration due to gravity. In this case, the forces acting on the box going down is the weight itself impeded by the friction between the box and the inclined plane.
The weight of the box is expressed as mg sin theta
The frictional force is expressed as the normal force times the coefficient of friction that is expressed as mu g cos theta.
By Newton's second law of motion, F = ma = mg sin theta - mu g cos theta
Thus, a = g (sin theta - u cos theta
Answer:
Well depending on who you are and what your personality type is then you could be just as involved and still not liking the sport. Some people will still pay just as much attention because they would not want to be a poor sport.
Explanation:
Can I have Brainliest please
The work done on the block is B) 400 J
Explanation:
The work done when lifting an object is equal to the change in gravitational potential energy of the object:
where
m is the mass of the object
g is the acceleration of gravity
is the change in height of the object
In this problem we have:
(mg) = 100 N is the weight of the block (product of mass and acceleration of gravity)
is the change in heigth of the object
Substituting, we find the work done:
Learn more about work:
brainly.com/question/6763771
brainly.com/question/6443626
#LearnwithBrainly