All categories

4 years ago

Give an example of when your average speed would be higher than instantaneous speed

1 answer:

3 0

When I drive to the office, I drive through two school zones,
and four intersections that are controlled by traffic lights.

My average speed for the trip is higher than my instantaneous
speed is at any point in the school zones, or at any time when
I'm waiting for a red light to change.

You might be interested in

Looking at systems is important in science because

Vikentia [17]

Answer:

systems help identify parts and simplify solutions.

Explanation:

Systems are very important in science because they are made up of many parts and can help simplify solutions better.

A system is made up of several parts that are interacting together as a whole. They are very important in solving scientific problems and looking introspectively into a problem.

The parts that makes up the system are equally important as the whole. Systems are typified by what transpires at the level of their parts. Viewing a problem from a system wide angle helps scientists have better knowledge and can be vital in solving scientific problems.

7 0

4 years ago

Calculate the force of gravity on the 1.2-kg mass if it were 1.9×107 m above earth's surface (that is, if it were four earth rad

Anettt [7]

Answer:

Force of gravity, F = 0.74 N

Mass of an object, m = 1.2 kg

Distance above earth's surface, $d=1.9\times 10^7\ m$

Mass of Earth, $M=5.97\times 10^{24}\ kg$

Radius of Earth, $r=6.37\times 10^6\ m$

We need to find the force of gravity above the surface of Earth. It is given by :

$F=G\dfrac{mM}{R^2}$

R = r + d

R = 25370000 m

$F=6.67\times 10^{-11}\times \dfrac{5.97\times 10^{24}\ kg\times 1.2\ kg}{(25370000\ m)^2}$

F = 0.74 N

So, the force of gravity on the object is 0.74 N. Hence, this is the required solution.

5 0

4 years ago

A lowly high diver pushes off horizontally with a speed of 2.00 m/s from the platform edge 10.0 m above the surface of the water

VladimirAG [237]

Answer:

(a) 1.6m

(b) 6.86m

Explanation:

This is a horizontal shooting problem, so we will use the following equations.

For horizontal distance x we use:

$x(t)=x_{0}+v_{0}t$

Where $x(t)$ is the horizontal distance at a time $t$ , $x_{0}$ is the initial horizontal position which in this case will be zero: $x_{0}=0$ . And $v_{0}$ is the initial speed: $v_{0}=2m/s$

So to solve (a):

(a) At what horizontal distance from the edge is the diver 0.800 s after pushing off?

we have that the time is: $t=0.8s$ so the horizontal distance is:

$x(0.8)=(2m/s)(0.8s)1.6m$

The answer for (a) is 1.6m

Now, to solve (b) we need the equation for vertical distance:

$y(t)=y_{0}-\frac{1}{2}gt^2$

Where $y(t)$ is the vertical distance at a time $t$ , $y_{0}$ is the initial vertical distance: $y_{0}=10m$ And $g$ is the gravitational acceleration: $g=9.81m/s^2$ }