A spring vibrates 120 times in 2 mins find its frequency and time period
1 answer:
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Answer:
0.00001 %
Explanation:
The distance from satellite = 20000 km
Position range = 2 m
The percentage uncertainty is given by dividing the distance from satellite by the position range of desired accuracy.
Percentage uncertainty is given by
The percentage uncertainty that is required is 0.00001 %
Answer:
A. 181.24 N
Explanation:
The magnitude of hte electrostatic force between two charged objects is given by the equation
where
k is the Coulomb's constant
q1, q2 are the magnitudes of the two charges
r is the separation between the charges
In this problem, we have:
is the magnitude of the 1st charge
is the magnitude of the 2nd charge
r = 2.5 cm = 0.025 m is the separation between the charges
Therefore, the magnitude of the electric force is:
So, the closest answer is
A) 181.24 N
Answer:
Explanation:
We know that,
"Frequency refers to the number of occurrences of a periodic event per time and is measured in cycles/second."
According to Question,
⇒ 5 seconds = 10 oscillations
⇒ 1 second = 10/5 oscillations
⇒ 1 second = 2 oscillations
In one second, there are 2 oscillations or cycles. The unit of frequency is Hertz. Hence, the frequency is <u>2</u><u> </u><u>Hertz</u>.