Answer:
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Answer:0.025576559594663 mole.
Explanation:
Answer :
the amount of heat,in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22°c to 66°c is 9.104 Joules.
Explanation:
The answer can be calculated using the formula
Q = mCрΔT
where
Q is the amount of heat required in joules to raise the temperature.
m is the mass of the sample in Kg.
Cp is the specific heat of the sample in J/Kg°C.
ΔT is the change in temperature required.
Here, m = 49.5-gram = 0.0495 kg
Cp = 4.18 J/Kg°C (for water)
T₁ = 22°C ; T₂ = 66°C
ΔT = 66 - 22 = 44
Substituting values in Q = mCрΔT
Q = (0.0495)(4.18)(44)
Q = 9.104 J
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Answer: Na2CO3 + 2 HCl → 2 NaCl + H2CO3
I hope this helped!
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- Zack Slocum
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Chemical reactions involve electrons and where they move (if they move).
Metal atoms (or elements) usually give away their outer shell electrons in reactions to become stabilised (creating positive ions). Non-metal atoms (or elements) usually gain electrons in order to become stable (negative ions). Some reactions involve covalent bonds, metallic bonds, ionic bonds etc., but at the base (no pun intended :D) of most chemical reactions it's just a matter of electrons moving around between atoms.
Hope it helps!
