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2 years ago

How did the discovery of eris force astronomers to reconsider the definition of planet?

Physics

1 answer:

kogti [31]2 years ago

5 0

Answer:

Explanation:

They had demoted Pluto on the basis of the discovery of Eris. They also discovered that Eris had a moon. It was thought to be much bigger than Pluto. That turned out not to be true. So having accepted Eris as a planet, they had to consider carefully what to do about Pluto. It has a gravitational constant of 0.82 m/s^2 which is 8.4% of that of our gravitational pull. and slightly more than Pluto.

Later data showed that these two objects in space were more like twins and that's what shook up the definition of a planet. You can't demote one and not the other.

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What type a medium is a ocean wave

andre [41]

Ocean waves travel through the medium called
"ocean water" or "salt water" or simply "water".

8 0

3 years ago

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620 J of heat is added to the cylinder of an engine, which causes the gas inside to expand. As a result, the piston of the engin

Maru [420]

Answer:

400 J work is done BY the engine.

The internal energy of the gas is 620 J

Explanation:

The given information are;

The heat added to the cylinder = 620 J

The force applied by the piston of the engine = 8.0 kN = 8,000 N

The distance over which the force moves (the piston) = 5.0 cm = 0.05 m

The work done (by the engine) = Force × Distance = 8,000 N × 0.05 m = 400 J

The internal energy is the sum of the kinetic and potential energy of the system

Therefore, given that the internal energy, U, is the sum total of the energy in the system

∴ U = The heat supplied to the system = 620 J

Which gives;

400 J work is done BY the engine.

The internal energy of the gas is 620 J.

6 0

2 years ago

Which of the following is a force acting between objects that do not touch?

kirill [66]

The answer is B friction force

3 0

2 years ago

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A small plastic ball with a mass of 7.00 10-3 kg and with a charge of +0.155 µC is suspended from an insulating thread and hangs

adell [148]

Answer:

the magnitude of the charge Q on each plate is $3.053 *10^{-8} \ C$

Explanation:

Given that :

mass (m) = $7.00 *10 ^{-3} \ kg$

charge (q) = +0.155 µC = $+0.155 *10^{-6}\ C$

angle $\theta = 30^0 \ C$

Area A on each plate = 0.0135 m²

From the diagram below;

$tan \ \theta = \frac{Eq}{mg}$ ----- equation (1)

Also by using Gauss Law ;

$Q = \epsilon_0 \phi$

$Q = \epsilon_0EA$ ----- equation (2)

Combination equation 1 and 2 together ; we have

$Q = \frac{\epsilon_0\ * \ m\ *\ g \ \ * \ tan \theta \ * \ A}{q}$

$Q = \frac{(8.85*10^{-12}C^2/N.m^2 )\ * \ (7.00*10^{-3} kg)\ *\ (9.8 m/s^2) \ \ * \ tan \(30 \ * \ (0.0135 m^2)}{0.155*10^{-6}\ C}$

$Q = 3.053 *10^{-8} \ C$

8 0

3 years ago

most waves approach the shore at an angle. however, they bend to be nearly parallel to the shore as they approach it because bla

Alex

Most waves approach the shore at an angle. However, they bend to be nearly parallel to the shore as they approach it because when a wave reaches a beach or coastline, it releases a burst of energy that generates a current, which runs parallel to the shoreline.

Most waves approach shore at an angle. As each one arrives, it pushes water along the shore, creating what is known as a longshore current within the surf zone.
Waves approach the coast at an angle because of the direction of prevailing wind.
The part of the wave in shallow water slows down, while the part of the wave in deeper water moves at the same speed.
Thus when wave reaches a beach or coastline, it releases a burst of energy that generates a current, which runs parallel to the shoreline.

To know more about waves visit:

brainly.com/question/27831266

#SPJ4

6 0

1 year ago