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2 years ago

How did the discovery of eris force astronomers to reconsider the definition of planet?

Physics

1 answer:

kogti [31]2 years ago

5 0

Answer:

Explanation:

They had demoted Pluto on the basis of the discovery of Eris. They also discovered that Eris had a moon. It was thought to be much bigger than Pluto. That turned out not to be true. So having accepted Eris as a planet, they had to consider carefully what to do about Pluto. It has a gravitational constant of 0.82 m/s^2 which is 8.4% of that of our gravitational pull. and slightly more than Pluto.

Later data showed that these two objects in space were more like twins and that's what shook up the definition of a planet. You can't demote one and not the other.

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Physics I’ll give brainiest! :)

Monica [59]

isotopes are the same element, but have different numbers of neutrons (but still have the same number of electrons and protons), hence have a different mass number.

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3 years ago

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If 10 waves pass a point each second and their wavelength is 30m, what is their speed?

svet-max [94.6K]

Answer:

300m/s

Explanation:

velocity = frequency(wavelength)

Since 10 waves pass a point each second, frequency is 10

therefore, speed = (10)(30 = 300m/s

5 0

3 years ago

HELP NOW PLEASE ANSWER THE QUESTION THE PICTURE IS ATTACHED BELOW

anastassius [24]

The answer is D

"a property of matter by which it continues in its existing state of rest or uniform motion in a straight line, unless that state is changed by an external force."

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2 years ago

A small, 300 g cart is moving at 1.20 m/s on an air track when it collides with a larger, 2.00 kg cart at rest?

stiv31 [10]

Answer:

The speed of the large cart after collision is 0.301 m/s.

Explanation:

Given that,

Mass of the cart, $m_1 = 300\ g = 0.3\ kg$

Initial speed of the cart, $u_1=1.2\ m/s$

Mass of the larger cart, $m_2 = 2\ kg$

Initial speed of the larger cart, $u_2=0$

After the collision,

Final speed of the smaller cart, $v_1=-0.81\ m/s$ (as its recolis)

To find,

The speed of the large cart after collision.

Solution,

Let $v_2$ is the speed of the large cart after collision. It can be calculated using conservation of momentum as :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

$m_1u_1+m_2u_2-m_1v_1=m_2v_2$

$v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}$

$v_2=\dfrac{0.3\times 1.2+0-0.3\times (-0.81)}{2}$

$v_2=0.301\ m/s$

So, the speed of the large cart after collision is 0.301 m/s.

4 0

3 years ago

A ruler of length 0.30m is pivoted at its centre. Equal and opposite forces of magnitude 2.0N are applied to the ends of the rul

kow [346]

Answer:

0.3858 Nm

Explanation:

The torque of the couple is the dot product of the force vector and the couple vector from 1 end of the ruler to the center. This equals to the product of their magnitude times the cosine() of the angle made by their direction:

$T = \vec{F} \cdot \vec{s} = Fscos(50^0) = 2 * 0.3 * 0.643 = 0.3858 Nm$

6 0

3 years ago