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jarptica [38.1K]
3 years ago
5

If 10 waves pass a point each second and their wavelength is 30m, what is their speed?

Physics
1 answer:
svet-max [94.6K]3 years ago
5 0

Answer:

300m/s

Explanation:

velocity = frequency(wavelength)

Since 10 waves pass a point each second, frequency is 10

therefore, speed = (10)(30 = 300m/s

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The noise floor, also known as additive white Gaussian noise (AWGN), is a continuous noise level that appears over a wide spectr
harkovskaia [24]

Answer:

correct option is a. True

Explanation:

solution

the noise floor is AWGN ( additive white Gaussian noise )  

and when viewed in the frequency domain, it is the continuous noise level  

because as they have a  uniform power over all the frequency.

 

so that it is additive white Gaussian noise  

as we can say given statement is True  

correct option a true  

4 0
3 years ago
A rock with a mass of 0.3 kg falls from the top of a cliff. If it takes the rock 2.5 s to reach the ground, what was the impulse
kaheart [24]
Impulse=force x time
force=mass x acceleration due to gravity
force=
300 \times 10 = 3000
impulse =3000 x 2.5= ( sorry i don't have a calculator right now so you must calculate this yourself)
I converted from kg to g because it is the standard.
Hope this helps you.
4 0
3 years ago
Energy transformations that involve one transformation from one type of energy to another are called...............transformatio
iragen [17]

Answer:

It is called single transformation

8 0
3 years ago
Read 2 more answers
Four forces are exerted on a disk of radius R that is free to spin about its center, as shown above. The magnitudes are proporti
Dmitry_Shevchenko [17]

The given magnitude of forces of F₁ = F₄, F₂ = F₃, F₁ = 2·F₂, give the

forces that exert zero net torque on the disk as the options;

(B) F₂

(D) F₄

<h3>How can the net torque on the disk be calculated?</h3>

The given parameters are;

F₁ = F₄

F₂ = F₃

F₁ = 2·F₂

Therefore;

F₄ = 2·F₂

In vector form, we have;

\vec{F_4} = \mathbf{\frac{\sqrt{3} }{2} \cdot F_4 \cdot \hat i -  0.5 \cdot F_4 \hat j}

\vec{F_2} = \mathbf{ -F_2 \,  \hat j}

Clockwise moment due to F₄, M₁ = -0.5 \times F_4 \,  \hat j  \times \dfrac{R}{2}

Therefore;

M_1  =- 0.5 \times 2 \times  F_2 \,  \hat j  \times \dfrac{R}{2} =   \mathbf{ -F_2 \,  \hat j  \times \dfrac{R}{2}}

Counterclockwise moment due to F₂ = -F_2 \,  \hat j  \times \dfrac{R}{2}

Given that the clockwise moment due to F₄ = The counterclockwise moment due to F₂, we have;

Two forces that combine to exert zero net torque on the disk are;

F₂, and F₄

Which are the options; (B) F₂, and (D) F₄

Learn more about the resolution of vectors here:

brainly.com/question/1858958

4 0
2 years ago
The chain of length L and mass per unit length rho is released from rest on the smooth horizontal surface with a negligibly smal
devlian [24]

Answer:

Part a)

a = \frac{x}{L} g

Part b)

T = \rho x g(1 - \frac{x}{L})

Part c)

v = \sqrt{gL}

Explanation:

Part a)

Net pulling force on the chain is due to weight of the part of the chain which is over hanging

So we know that mass of overhanging part of chain is given as

m = \rho x

now net pulling force on the chain is given as

F = \rho x g

now acceleration is given as

F = Ma

\rho x g = \rho L a

a = \frac{x}{L} g

Part b)

Tension force in the part of the chain is given as

mg - T = ma

\rho x g - T = \rho x a

\rho x(g - a) = T

\rho x (g - \frac{x}{L} g) = T

T = \rho x g(1 - \frac{x}{L})

Part c)

velocity of the last link of the chain is given as

a = \frac{x}{L} g

v\frac{dv}{dx} = \frac{x}{L} g

now integrate both sides

\int v dv = \frac{g}{L} \int x dx

\frac{v^2}{2} = \frac{gL}{2}

v = \sqrt{gL}

3 0
3 years ago
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