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ExtremeBDS [4]
3 years ago
7

One of the factors that determines the ? of a capacitor is the frequency measured in hertz.

Physics
2 answers:
Amanda [17]3 years ago
5 0

Answer:

<h2>One of the factors that determines the <u>reactance</u> of a capacitor is the frequency measured in hertz.</h2>

Explanation:

<em>Capacitive reactance is  the opposition offered to the passage of alternating current.</em>

<em />

The capacitive reactance is defined as

X_{C}=\frac{10^{6} }{2 \pi f C}

Where X_{C} is the capacitive reactance in ohms, f is the AC frequency in hertz and C is the capacitance in microfarads.

This mathematical definition stablish a relation between capactivie reactance and frequency, actually these two are inversely proportional, that is, more frequency means less capacitive reactance.

Therefore, the word that completes the statement is reactance.

olchik [2.2K]3 years ago
4 0

Answer:

The reactance of the capacitor

Explanation:

In an AC circuit containing different elements (capacitors, resistors and inductors), we cannot simply calculate the equivalent resistance of the circuit, so another quantity is used, which is called reactance.

For a capacitor, the reactance is given by:

X=\frac{1}{2 \pi f C}

where:

f is the frequency of the AC current in the circuit

C is the capacitance of the capacitor

The reactance has a similar meaning to that of the resistance for a DC current. In fact, we notice that:

- When f=0 (which means we are in regime of DC current, because the current never changes direction), the reactance is infinite. This is correct: in a DC circuit, the capacitor does not let current pass through it, so it like it has infinite resistance (=infinite reactance)

- When f tends to infinite, the reactance becomes zero: in such situation, the current in the circuit changes direction so quickly that the capacitor has no enough time to "block" the current in the circuit, so it like it has almost zero resistance (zero reactance).

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IrinaVladis [17]

Answer:

13.18 m/s

Explanation:

Let the velocity of sports utility car is

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mc = 1200 kg, uc = 31.1 m/s

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Using conservation of momentum

mc × uc + ms × us = 0

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u = 13.18 m/s

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3 years ago
EXTREME HELP!!!!
mrs_skeptik [129]

the anwser is c is always the best anwser


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Practice entering numbers that include a power of 10 by entering the diameter of a hydrogen atom in its ground state, dH = 1.06
Slav-nsk [51]

Answer:

1.06085\times 10^{-10}\ m

Explanation:

h = Planck's constant = 6.626\times 10^{-34}\ m^2kg/s

m = Mass of electron = 9.11\times 10^{-31}\ kg

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

e = Charge of electron = 1.6\times 10^{-19}\ C

n = 1 (ground state)

Angular momentum is given by

L=mvr

From Bohr's atomic model we have

L=\dfrac{nh}{2\pi}

mvr=\dfrac{nh}{2\pi}\\\Rightarrow v=\dfrac{nh}{2\pi mr}

The centripetal force will balance the electrostatic force

\dfrac{ke^2}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow \dfrac{ke^2}{r}=mv^2\\\Rightarrow \dfrac{ke^2}{r}=m(\dfrac{nh}{2\pi mr})^2\\\Rightarrow r=\dfrac{n^2h^2}{4\pi^2mke^2}\\\Rightarrow r=\dfrac{1^2\times (6.626\times 10^{-34})^2}{4\pi^2 \times 9.11\times 10^{-31}\times 8.99\times 10^{9}\times (1.6\times 10^{-19})^2}\\\Rightarrow r=5.30426\times 10^{-11}\ m

The diameter is 2\times 5.30426\times 10^{-11}=1.06085\times 10^{-10}\ m

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3 years ago
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What would be the coefficient of performance if the refrigerator (operating between the same temperatures) was instead used as a
viktelen [127]

Complete Question

A certain refrigerator, operating between temperatures of -8.00°C and +23.2°C, can be approximated as a Carnot refrigerator.

What is the refrigerator's coefficient of performance? COP

(b) What If? What would be the coefficient of performance if the refrigerator (operating between the same temperatures) was instead used as a heat pump? COP

Answer:

a

 COP = 8.49

b

  COP_1 = 9.49  

Explanation:

From the question we are told that

     The lower operation temperature of refrigerator is  T_1 =  -8.00^oC =  265 \  K

     The upper operation temperature of the refrigerator is   T_2 =  23.2 ^oC =  296.2 \  K

Generally the refrigerators coefficient of performance is mathematically represented as

        COP =  \frac{T_1}{T_2 - T_1  }

=>     COP =  \frac{265}{296.2 - 265  }

=>     COP = 8.49

Generally if a refrigerator (operating between the same temperatures) was instead used as a heat pump , the coefficient of performance is mathematically represented as

            COP_1 =  \frac{T_2}{ T_2 - T_1}  

=>         COP_1 =  \frac{296.2}{ 296.2 - 265 }  

=>         COP_1 = 9.49  

8 0
3 years ago
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