Answer:
(a) The proportion of dry air bypassing the unit is 14.3%.
(b) The mass of water removed is 1.2 kg per 100 kg of dry air.
Explanation:
We can express the proportion of air that goes trough the air conditioning unit as 
and the proportion of air that is by-passed as 
, being 
.
The amount of water that goes into the drier inlet has to be 0.004 kg/kg, and can be expressed as:
Replacing the first equation in the second one we have
(b) Of every kg of dry air feed, 85.7% goes in to the air conditioning unit.
It takes (0.016-0.002)=0.014 kg water per kg dry air feeded.
The water removed of every 100 kg of dry air is
It can also be calculated as the difference in humiditiy between the inlet and the outlet: (0.016-0.004=0.012 kgW/kDA) and multypling by the total amount of feed (100 kgDA).
100 * 0.012 = 1.2 kgW
Answer:
22.715 moles of oxygen are used
Explanation:
Given data:
Number of moles of ethane = 6.49 mol
Number of moles of O₂ required = ?
Solution:
Chemical equation:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
Now we will compare the moles of oxygen with ethane.
C₂H₆ : O₂
2 : 7
6.49 : 7/2×6.49 = 22.715 mol
Thus, 22.715 moles of oxygen are used.
Explanation: i stuck at this Answer:Sometimes atoms share more than one pair of electrons, for example a double covalent bond can occur, as in the carbon dioxide molecule where carbon shares 2 pairs of electrons with each oxygen atom: O=C=O. (where = represents a double bond). Another kind of covalent bonding is called co-ordinate or dative covalent.
The chemical formula for zinc is Zn, and HCl for hydrogen chloride. The complete balanced equation for these reactants would be:
Zn + 2 HCl → ZnCl₂ + H₂
The stoichiometric coefficient 2 for HCl is essential to obey the Law of Conservation of Mass. The elements before and after the reaction must be equal in amounts.
Above question is incomplete. Complete question is
<span>What is the missing number in the nuclear reaction 175 78 pt -- 4 2 He plus 76 Os?
....................................................................................................................
Solution:
Reaction involved in present nuclear event is
</span>175 78 Pt → 4 2 He + 76 Os
In above nuclear reaction, atomic mass number of Os is missing. The atomic mass number of Os = 175 - 4 = 171
Thus, complete nuclear can be written as
175 78 Pt → 4 2 He + 171 76 Os
