Because g(x) passes from 1,0 to 1,4, we can say that it has a slope of 0. f(x) has a slope of 2.
Steps to find the equation
1. Find the slope
2. Insert slope into the general equation
3. Find y-intercept
4. Insert -intercept into the equation found in step 2
And you get the equation of the line
----------------------------------------------------------------------------------------------
Find the slope
----------------------------------------------------------------------------------------------
2y - x = 4
----------------------------------------------------------------------------------------------
Rewrite into the form y = mx + c
----------------------------------------------------------------------------------------------
2y = x + 4
y = 1/2 x + 2
Slope = 1/2
Perpendicular slope = -2 (negative reciprocal)
----------------------------------------------------------------------------------------------
Insert slope into the equation
----------------------------------------------------------------------------------------------
y = mx + c
y = -2x + c
----------------------------------------------------------------------------------------------
Find y-intercept
----------------------------------------------------------------------------------------------
y = -2x + c
At point (1, 2)
2 = -2(1) + c
2 = -2 + c
c = 4
----------------------------------------------------------------------------------------------
Insert y-intercept into the equation y = -2x + c
----------------------------------------------------------------------------------------------
y = -2x + 4
----------------------------------------------------------------------------------------------
Answer: y = -2x + 4
----------------------------------------------------------------------------------------------
Yes, because two batches of dough equals 48 cookies. So she would need 3 batches, equaling to 72 cookies.
just substitute 3 in for x.
(15- 4 x 3) + 5
4 x 3 = 12
15 - 12 = 3
3 + 5 = 8
<em><u>Hope this is correct!</u></em>
Let's look at numbers with the same digit in different places and see if we can determine some relationship.
Consider the number 20.
Now, consider the number 200, which has the 2 in the location just to the left of where it is in 20. You're expect to observe that the number 200 is <em>ten times</em> the number 20.
Consider the number with the 2 in the position to the right of where it is in 20. That number is 2. You are expected to observe that the number 2 is <em>one-tenth</em> the number 20.
The place-value of a digit increases by a factor of 10 when moved one place left, and is reduced by a factor of 1/10 when moved one place right.
_____
This is what makes a place-value number system work. In Roman Numerals, for example, the value of a character is changed by ...
- putting it ahead of or after a higher-value character: IV, VI
- changing the character: I, V, X, L, C, D, M
Place-value number systems don't have to have 10 as their base. We use 60 for the base in (minutes):(seconds), both for time and angle measures. We use 2, 8, or 16 as the base in the binary, octal, and hexadecimal numbers used by computer systems. These other place-value systems have the same characteristic: the value of a digit is increased by a factor of the base when moved to the left, and decreased by a factor of the base when moved to the right. (The hexadecimal value A7C0 has 16 times the value of A7C, for example, and 1/16th the value of A7C00.)
