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DedPeter [7]
3 years ago
15

What does this mean and how do I answer?

Chemistry
1 answer:
Tamiku [17]3 years ago
4 0

Answer:

No

Explanation:

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Question 2 (Multiple Choice Worth 2 points)
faust18 [17]

Answer:

\pi r²  x h

Explanation:

A can is cylindrical in nature. Using the formula of the volume of the can, we can find this unknown volume.

The volume of cylinder is given as:

   Volume of a cylinder  = Area x height

  Volume of  a cylinder = \pi r²  x h

Therefore density of the can;

      Density  = \frac{mass}{volume}

6 0
3 years ago
Which phrase best describes how scientists use the data they collect
lozanna [386]

Answer:

The correct answer is b

7 0
3 years ago
Read 2 more answers
How many significant figures does 104,000 have
JulijaS [17]

Answer:

104,000 has 3 significant figure.

Explanation:

This is because all non-zero digits are significant and zeros in between non-zero digits are significant.

7 0
3 years ago
In 1909 Fritz Haber discovered the workable conditions under which nitrogen, N2(g), and hydrogen, H2(g), would combine using to
labwork [276]

Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

Solution : Given,

Mass of NH_3 = 100 g

Molar mass of NH_3 = 27 g/mole

Molar mass of N_2 = 28 g/mole

First we have to calculate moles of NH_3.

\text{ Moles of }NH_3=\frac{\text{ Mass of }NH_3}{\text{ Molar mass of }NH_3}= \frac{100g}{27g/mole}=3.7moles

The given balanced chemical reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

From the given reaction, we conclude that

2 moles of NH_3 produced from 1 mole of N_2

3.7 moles of NH_3 produced from \frac{1mole}{2mole}\times 3.7mole=1.85moles of N_2

Now we have to calculate the mass of N_2.

Mass of N_2 = Moles of N_2 × Molar mass of N_2

Mass of N_2 = 1.85 mole × 28 g/mole = 51.8 g

Therefore, 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

5 0
3 years ago
Calculate the mass percent of 0.485 g of H, which reacts with oxygen to form 2.32 g H2O
Nataly [62]

Answer:

Mass % of hydrogen = 20.9 %

Explanation:

Given data:

Mass of hydrogen = 0.485 g

Mass of water = 2.32 g

Mass percent of hydrogen = ?

Solution:

Mass % of hydrogen = mass of hydrogen / mass of water × 100

Mass % of hydrogen = 0.485 g/ 2.32 g × 100

Mass % of hydrogen = 0.209  × 100

Mass % of hydrogen = 20.9 %

4 0
3 years ago
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