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Oxana [17]
3 years ago
15

Đoạn dây dẫn thẳng có dòng điện I chạy qua, đặt trong từ trường

Physics
1 answer:
umka21 [38]3 years ago
4 0

<em>A straight piece of wire with a current I flowing through it is placed in a magnetic field</em>

<em>A straight piece of wire with a current I flowing through it is placed in a magnetic fielduniform and perpendicular to the magnetic field lines. Magnetic force acting on the string</em>

<em>A straight piece of wire with a current I flowing through it is placed in a magnetic fielduniform and perpendicular to the magnetic field lines. Magnetic force acting on the stringthere is a way</em>

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A wave's frequency is 2Hz and its wavelength is 4 m. What is the wave's speed?
icang [17]

Wave speed = (wavelength) x (frequency)

                       =      (4 m)        x  (2 /sec)

                       =               8 m/sec

7 0
4 years ago
To determine power, it is necessary to know the A. energy required and the time it takes. B. amount of work and the distance cov
Y_Kistochka [10]
The answer for this would be A. since power is Joules/seconds and energy is rated in Joules
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3 years ago
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Since there are no aurora observed on Venus we can conclude that Venus a. lacks atmospheric oxygen b. is too hot for magnetic fo
Brrunno [24]

Answer:

Yes, Venus does not have the same magnetic field as that of earth's  

Explanation:

Instead, there are solar wind particles that can deeply penetrate the venus atmosphere and can collide with the other carbon atoms already present in the air but lacks oxygen and thus does not have that strong magnetic field which would deflect the suns rays and create aurora in the sky at night.

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Humans can hear the squeaks and clicks that bats emit while using echolocation to see their surroundings
MA_775_DIABLO [31]

Answer:

False?

Explanation:

Hope this helps you!

If this is wrong next time I will be better!

5 0
3 years ago
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A pump is used to send water through a hose, the diameter of which is 10 times that of the nozzle through which the water exits.
Keith_Richards [23]

Use VFR1 = VFR2 to discover the velocity at in the hose VFR = A * V

D hose =10 * D nozzle, R hose = 5 * D nozzle

Area of a circle = πR^2

Area h=3.14*25*D^2 = 75.5D^2

(Radius=Diameter/2) area n = 3.14*(D^2/4) = .785D^2

 

Use VFR = VFR v2 = 0.4m/s

0.4*.785D^2 = 75.5*D^2* v1 D^2

= .314 =75.5*V1

v1 = 0.004m/s

 

Now we have the velocity, we can use Bernoulli's equation.

P1+ρgh1+ρV1^2 /2 = constant

There is no atmospheric pressure before so the P1= the gauge pressure at the pump, let’s call the height of the hose 0m and the height of the nozzle 1m so the is no ρgh1 Likewise, there is only atmospheric pressure at the nozzle which is 100000 PA, and lastly the density ρ of water is 1000 KG/M^3

Pg + 1000*.004^2/2 = 100000+1000*9.8*1+ 1000*0.4^2/2

Pg + .008= 100000+9800+80

Pg+.008= 109880

Pg=109880.008 PA

3 0
3 years ago
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