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Andrews [41]
3 years ago
5

Use this technique to find a formula for the intensity I of a sound, in terms of the sound level β and the reference intensity I

0. There will be a quantity (10 dB) involved in your calculations. When you enter your answer, leave off the unit dB. Express your answer in terms of β and I0.
Physics
1 answer:
mezya [45]3 years ago
8 0

The problem is basically asking us to find a way to find the sound intensity I, in terms dependent on the sound level and the reference intensity I_0.For this purpose we can start from the unit used in the scale logarithmic decibel, that is

\beta = 10log_{10}\frac{I}{I_0}

Where

I = Acoustic intensity on the linear scale

I_0 = Hearing threshold

Using the logarithmic properties of the exponents the above expression can be described as:

(\frac{I}{I_0})^{10} = 10^{\beta}

I = I_0 10^{\frac{\beta}{10}} \righarrow that is the expression or technique to find the intensity of sound.

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