C=12 g/mole
H=1 g/mole
O=16 g/mole
2(12)+6(1)+16=46 g/mole C2H6O
46 g/27 g =1 mole/x mole⇒ x≈0.58
the answer is about 0.58. hope helped ;)
2Cr”(as)+hc(g)>2Cr(s)+6H*(sa)
Answer : If a substance is the limiting reactant, then it limits the formation of products because in the reaction it is present in limited amount.
Explanation :
While observing a chemical reaction, we can tell about whether a reactant is limiting or excess.
Step 1 : first write the chemical reaction and then balanced the chemical equation.

Step 2 : convert the given masses into the moles if mass of
is 10.5 g and molar mass of
is 28 g/mole and the mass of hydrogen is 0.40 g and molar mass of hydrogen is 2 g/mole.


Step 3 : Now we have to determine the limiting reagent and excess reagent.

Now we conclude that
is the limiting reagent and hydrogen is an excess reagent.
Hypothesis :
Limiting reagent : It is the reagent in the chemical reaction that is totally consumed when the chemical reaction is complete. Limiting reagent limits the formation of products.
Answer:
CH3F
Explanation:
because if drawn out its is asymmetric
If in the following diagram the substance is in the solid state during stage 1, during stage 2 the substance is boiling or condensing .
Boiling<span> is the term used to describe the rapid vaporization of a liquid. Boiling occurs when a liquid is heated to its </span>boiling<span> point.
</span>Condensation happens when the gas is changed into liquid.