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2 years ago

SOMEONE PLEASE HELP ME ASAP PLEASE!!!

Mathematics

1 answer:

melamori03 [73]2 years ago

7 0

Answer:

3.6

Step-by-step explanation:

d = sqrt(3^2+2^2) = sqrt(13) = 3.6

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Can you guys help me solve this equation with step-by-step help, please...

Alex

Step-by-step explanation:

-2x - 5y = 16___(1)

2x - 3y = -16___(2)

(1) + (2) ==> -2x -5y = 16

(+) 2x -3y = -16

-8y = 0

y = 0/-8

y = 0

y=0 in (1)

(1)---> -2x-5y =16

-2x - 5(0) = 16

-2x - 0 = 16

-2x = 16

x = 16/-2

x = -8

x = -8 , y = 0

-5x + 2y = 11__(1) ; -3x + 4y = -13___(2)

multiply eqn(1) with 2

2 × (1) : -10x + 4y = 22___(3)

(3) - (2) :. -10x + 4y = 22

(-) -3x + 4y = -13

-7x = 35

x = 35/-7

x = -5

x=-5 in (1)

(1) : -5x + 2y = 11

-5(-5) + 2y = 11

25 + 2y = 11

2y = 11 - 25

2y = -14

y = -14/2

y = -7

x = -5 , y = -7

4 0

1 year ago

Round 1244 to the nearest thousand

Marta_Voda [28]

Answer:

1000

if the number before it is 5 or more you round up if its 4 or less you leave it alone

7 0

2 years ago

Read 2 more answers

If f(x, y, z) = x sin(yz), (a) find the gradient of f and (b) find the directional derivative of f at (2, 4, 0) in the direction

valentina_108 [34]

Answer:

a) $\nabla f(x,y,z) = \sin{yz}\mathbf{i} + xz\cos{yz}\mathbf{j} + xy \cos{yz}\mathbf{k}$ .

b) $Du_{f}(2,4,0) = -\frac{8}{\sqrt{11}}$

Step-by-step explanation:

Given a function $f(x,y,z)$ , this function has the following gradient:

$\nabla f(x,y,z) = f_{x}(x,y,z)\mathbf{i} + f_{y}(x,y,z)\mathbf{j} + f_{z}(x,y,z)\mathbf{k}$ .

(a) find the gradient of f

We have that $f(x,y,z) = x\sin{yz}$ . So

$f_{x}(x,y,z) = \sin{yz}$

$f_{y}(x,y,z) = xz\cos{yz}$

$f_{z}(x,y,z) = xy \cos{yz}$ .

$\nabla f(x,y,z) = f_{x}(x,y,z)\mathbf{i} + f_{y}(x,y,z)\mathbf{j} + f_{z}(x,y,z)\mathbf{k}$ .

$\nabla f(x,y,z) = \sin{yz}\mathbf{i} + xz\cos{yz}\mathbf{j} + xy \cos{yz}\mathbf{k}$

(b) find the directional derivative of f at (2, 4, 0) in the direction of v = i + 3j − k.

The directional derivate is the scalar product between the gradient at (2,4,0) and the unit vector of v.

We have that:

$\nabla f(x,y,z) = \sin{yz}\mathbf{i} + xz\cos{yz}\mathbf{j} + xy \cos{yz}\mathbf{k}$

$\nabla f(2,4,0) = \sin{0}\mathbf{i} + 0\cos{0}\mathbf{j} + 8 \cos{0}\mathbf{k}$ .

$\nabla f(2,4,0) = 0i+0j+8k=(0,0,8)$

The vector is $v = i + 3j - k = (1,3,-1)$

To use v as an unitary vector, we divide each component of v by the norm of v.

$|v| = \sqrt{1^{2} + 3^{2} + (-1)^{2}} = \sqrt{11}$

$v_{u} = (\frac{1}{\sqrt{11}}, \frac{3}{\sqrt{11}}, \frac{-1}{\sqrt{11}})$

Now, we can calculate the scalar product that is the directional derivative.

$Du_{f}(2,4,0) = (0,0,8).(\frac{1}{\sqrt{11}}, \frac{3}{\sqrt{11}}, \frac{-1}{\sqrt{11}}) = -\frac{8}{\sqrt{11}}$

6 0

2 years ago

(3x^2 + 8x - 4 ) -(-x^2 +5x +2) simplify

xxMikexx [17]

Answer:

4x^2+3x-6

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A water tank holds 200 gallons but is leaking at a rate of 3 gallons per week. A second water tank holds

vlada-n [284]

200-3w = 300-5w

Where w is the number of weeks

Rearrange and reduce:
-3w + 5w = 300-200
2 w = 100
w = 100/2 = 50 weeks

5 0

2 years ago

SOMEONE PLEASE HELP ME ASAP PLEASE!!!​

SOMEONE PLEASE HELP ME ASAP PLEASE!!!