<span><span>y = 2 + 2sec(2x)
The upper part of the range will be when the secant has the smallest
positive value up to infinity.
The smallest positive value of the secant is 1
So the minimum of the upper part of the range of
y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4
So the upper part of the range is [4, )
The lower part of the range will be from negative infinity
up to when the secant has the largest negative value.
The largest negative value of the secant is -1
So the maximum of the lower part of the range of
y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0
So the lower part of the range is (, 0].
Therefore the range is (, 0] U [4, )
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you have a 1/6 probability of rolling a 6
so for 3 6's it would be
1/6 x 1/6 x 1/6 = 1/216
Given:
Pool swimming Ocean swimming Total
Age 30 and younger 228 54 282
Over 30 years old 142 185 327
total 370 239 609
Frequencies:
Pool swimming Ocean swimming Total
Age 30 and younger 228/609 = 0.37 54/609 = 0.09 282/609 = 0.46
Over 30 years old 142/609 = 0.23 185/609 = 0.30 327/609 = 0.54
<span>total 370/609 = 0.61 239/609 = 0.39 609/609 = 1.00</span>
<span>The relative frequency (rounded to the nearest hundredth) of a person over 30 years old who prefers to swim in the ocean is 0.30</span>
It is c
Rhomuses are slanted squares
