Answer:
P₂ = 252 W
Explanation:
The electrical power is
P = V I
The potential difference is
V = I R
I = V / R
Let's replace
P = V² / R
Let's use the given values to calculate the resistance of the bulb
R = V² / P
R = 120²/75
R = 192 ohm
This resistance value does not depend on the applied voltage, so it is constant
Let's calculate the power in Europe
P₂ = V₂² / R
P₂ = 220²/192
P₂ = 252 W
the bulb dissipates much more power
Answer:
A chain reaction will be sustained in a sub-critical mass.
Explanation:
Hope this helps!
If not, I am sorry.
The answer is b) false. Stars are mainly classified by their spectra (the elements they absorb) and their temperature.
Answer:
sum of the two forces as both point to the right is a force that points to the right,
Explanation:
The force on the cast load at point Y is given by
F = q_y E
force is a vector magnitude so its result is
∑ F = Fₐ + F_b
indicate that the charge at y is negative, we analyze the direction of the force created by each charge
Charge A
as the electric field is incoming the charge is negative and as the test charge is negative both repel each other, consequently the force points to the right
Charge B
in this case the electric field lines are salient, therefore the charge is positive, consequently the force on the charge at y is attractive and points to the right
the sum of the two forces as both point to the right is a force that points to the right, that is, in the direction of the charge located at B
Answer:
Option 2 - Standard deviation
Explanation:
To find : Which measure of dispersion indicates the extent to which each individual score in a data set varies from the mean of that set?
Solution :
Standard deviation is defined as,
- It is a mathematical measure that is used to evaluate the difference between the mean value of a set of number and each value in the group.
- It is calculated as the square root of variance by determining the variation between each data point relative to the mean.
The measure of dispersion that indicates how much scores in a sample vary around the mean of the sample is the standard deviation.
Therefore, option 2 is correct.
