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LUCKY_DIMON [66]
3 years ago
5

PLZ help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Physics
1 answer:
vlada-n [284]3 years ago
6 0

Answer:

The leftmost red square.

Explanation:

As the earth surface we are looking at is moving toward the right, the impact point of the wind would be left of the original appearing target.

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Sphinxa [80]
Water is a really good conductor of sound so I would have to say that it would be to send the message underwater because a more dense medium produces a louder sound
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3 years ago
The car travels 25 miles in the first 0.5 hours
Westkost [7]

Answer:

\huge\boxed{\sf v = 50\ miles / hr}

Explanation:

<u>Given Data:</u>

Distance = S = 25 miles

Time = t = 0.5 hours

<u>Required:</u>

Speed = v = ?

<u>Formula:</u>

v = S/t

<u>Solution:</u>

v = 25 / 0.5

v = 50 miles / hr

\rule[225]{225}{2}

Hope this helped!

<h3>~AnonymousHelper1807</h3>
4 0
3 years ago
9. Know the three types of muscles, their shape, and where they are located.
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Cardiac, smooth, and skeletal. cardiac muscle cells are located in the walls of the heart and appear striated and are under involuntary control. smooth muscle fibers are located in walls of hollow visceral organs except the heart they also appear striated. skeleton muscle is found between bones and uses tendons to connect to the epimysium to the periosteum, or the outer covering of bone. skeletal muscle is shaped and adapted in many ways.


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8 0
3 years ago
A moving roller coaster speeds up with constant acceleration for 2.3s until it reaches a velocity of 35m/s. During this time, th
nata0808 [166]
Hope this answer helps: option B

Explanation:

9 0
3 years ago
What do you think would happen to the force of attraction of two interacting charges if their distance apart is halved?
sweet [91]

Answer:

The new force becomes 4 times the initial force.

Explanation:

The force of attraction or repulsion is given by the relation as follows :

F=k\dfrac{q_1q_2}{d^2}

Where

d is the distance between the interacting charges

F is inversely proportional to the distance between charges.

If the distance is halved, d'=(d/2), new force is given by :

F'=k\dfrac{q_1q_2}{d'^2}\\\\=k\dfrac{q_1q_2}{(\dfrac{d}{2})^2}\\\\=k\dfrac{q_1q_2}{\dfrac{d^2}{4}}\\\\=4\times \dfrac{kq_1q_2}{d^2}\\\\F'=4F

So, the new force becomes 4 times the initial force.

4 0
3 years ago
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