The correct answer to this question is false
Answer:
0.06 N
1.08 m/s
Explanation:
m = mass of the fan cart = 0.250 kg
a = acceleration of the fan cart = 24 cm/s² = 0.24 m/s²
F = Net force on the cart
Net force on the cart is given as
F = ma
F = (0.250) (0.24)
F = 0.06 N
v₀ = initial velocity of the cart = 0 m/s
v = final velocity of the cart
t = time interval = 4.5 s
Using the equation
v = v₀ + a t
v = 0 + (0.24) (4.5)
v = 1.08 m/s
<u>Communications:</u> Laura develops programs that flag suspicious network activity.
<h3>What is
communication?</h3>
Communication involves the transfer of information from one person (sender) to another (recipient), especially through the use of semiotics, symbols, signs and network devices.
<h3>How to match the scenarios?</h3>
- <u>Communications:</u> Laura develops programs that flag suspicious network activity.
- <u>Healthcare:</u> Greg calibrates electronic scales.
- <u>Manufacturing:</u> Tim ensures the output of a process remains in a defined range.
Read more on communication here: brainly.com/question/26152499
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Force is directly proportional to rate of change of velocity so it increasing, velocity (motion of the object) will also increase.
Hope this helps!
Answer:
The force applied on one wheel during braking = 6.8 lb
Explanation:
Area of the piston (A) = 0.4 
Force applied on the piston(F) = 6.4 lb
Pressure on the piston (P) = 
⇒ P = 
⇒ P = 16 
This is the pressure inside the cylinder.
Let force applied on the brake pad = 
Area of the brake pad (
)= 1.7
Thus the pressure on the brake pad (
) = 
When brake is applied on the vehicle the pressure on the piston is equal to pressure on the brake pad.
⇒ P =
⇒ 16 =
⇒ = 16 ×
Put the value of we get
⇒ = 16 × 1.7
⇒ = 27.2 lb
This the total force applied during braking.
The force applied on one wheel = 
= 
= 6.8 lb
⇒ The force applied on one wheel during braking.
