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Lapatulllka [165]
3 years ago
15

Suppose you give a 10 Newton push to Ryan on skis (he weighs 50 kg), how much will he accelerate?

Physics
1 answer:
Talja [164]3 years ago
3 0

Well we can just use F=ma. The force is 10N, the mass is 50 kg, solve for a. Well since we kg and N, no conversion is necessary. So just plugging in the numbers, we get

10N = 50 kg · a

\frac{10N}{50kg}=a

A newton is just \frac{kg·m}{s^{2}}

a=\frac{\frac{10kg·m}{s^{2}}}{50kg}

The s^2 and 50 kg you multiply

a=\frac{10kg·m}{50kg·s^{2}}

The kg's cancel and 10/50 is 1/5

\frac{1}{5}·\frac{m}{s^{2}}

So the acceleration is 1/5 m/s^2


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an object has a displacement of + 12 m in 6 seconds if the average velocity is found using the equation change in position / ela
rosijanka [135]

Answer:

+2m/s

Explanation:

average   velocity = displacement traveled / total time taken

                           = +12m/ 6s

                           = +2 m/s

6 0
3 years ago
Vector a has a magnitude of 12.3 units and points due west. vector b points due north. what is the magnitude of b if a - b has a
algol [13]

The magnitude of vector b is 8.58 Unit.

Since both the vectors a and b are perpendicular to each other, so we can apply the Pythagoras theorem to calculate the magnitude of the vector b.

Applying the Pythagoras theorem

(a-b)^2=a^2+b^2

15^2=12.3^2-b^2

b=8.58 unit

Therefor the magnitude of the vector b is 8.58 unit.

8 0
3 years ago
Which body systems help these cells get the energy they need?
PSYCHO15rus [73]

I believe there should be some sort of table attached. Unfortunately I cannot answer this question. Sorry!

5 0
3 years ago
A 13.0-g wad of sticky clay is hurled horizontally at a 110-g wooden block initially at rest on a horizontal surface. The clay s
Alisiya [41]

Answer:

v_{ic}=92.53 m/s

Explanation:

We need to apply conservation of momentum and energy to solve this problem.

<u>Conservation of momentum</u>

p_{i}=p_{f}

m_{c}v_{ic}=(m_{c}+m_{w})V (1)

  • m(c) is the mass of stick clay
  • m(w) is the mass of the wooden block
  • v(ic) is the initial velocity of clay
  • V is the final velocity of the system clay plus wood.

<u>Conservation of total energy</u>

The change in kinetic energy is equal to the change in internal energy, in our case it would be the energy loss due to the friction force. Let's recall the definition of work, it is the dot product between force and displacement, Therefore:

\Delta E=W

\frac{1}{2}(m_{c}+m_{w})V^{2}=F_{friction}*d

\frac{1}{2}(m_{c}+m_{w})V^{2}=\mu (m_{c}+m_{w})gd

We can find V from this equation:

V=\sqrt{2\mu gd}=\sqrt{2*0.65*9.81*7.5}=9.78 m/s

Now, let's put V into the equation (1) and find v(ic)

v_{ic}=\frac{(m_{c}+m_{w})V}{m_{c}}=\frac{123*9.78}{13}=92.53 m/s

I hope it helps you!  

<u />

8 0
3 years ago
Peter does 3,000 joules (J) of work by moving an object 40 meters (m). What is the force that Peter applies to the object? A 75
Papessa [141]

The force that peter applies to the object of distance 40m is 75N.

<h3>HOW TO CALCULATE FORCE</h3>

The force applied to an object can be calculated by dividing the work done on the object by the distance moved. That is;

Force = Work done ÷ distance

According to this question, the work done is 3000 joules while the distance moved is 40m. The force is calculated as follows:

Force = 3000J ÷ 40m

Force = 75N

Therefore, the force that peter applies to the object of distance 40m is 75N.

Learn more about force at: brainly.com/question/26115859

4 0
2 years ago
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