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4 years ago

Why is acceleration measured in meters / seconds squared? plz use your own words

2 answers:

8 0

Acceleration is velocity over time, and velocity is displacement over time. (This explains why time is squared.) As for the units, physicists (as well as pretty much any other kind of scientist) rely on SI units, which are the units generally accepted by scientists world-wide. Meters are the SI unit for length, and seconds are the SI unit for time.

oksano4ka [1.4K]4 years ago

6 0

This is because to find acceleration, you must divide velocity by time. Velocity is measured in meters / second, and time is measured in seconds. So, when meters / second is divided by seconds, the units become meters / second squared.

Hope this helps

Tobey

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Suppose that you wish to construct a simple ac generator having an output of 12 V maximum when rotated at 60 Hz. A uniform magne

Nostrana [21]

Answer:

The number of turns is 64.

Explanation:

Given that,

Magnetic field = 0.050 T

Area of coil = 100 cm²

Frequency = 60 Hz

Output voltage emf= 12 V

We need to calculate the number of turns

Using formula of induced emf

$emf =NAB\omega$

$N=\dfrac{emf}{A\times B\times2\pi f}$

$N=\dfrac{12}{0.01\times0.050\times2\times3.14\times60}$

$N =63.6 = 64\ turns$

Hence, The number of turns is 64.

5 0

3 years ago

Read 2 more answers

At noon, the temperature was 12º. it rose 8º during the afternoon, and then dropped 28º by midnight. what was the temperature at

djverab [1.8K]

At midnight, the temperature was -8 degrees.

7 0

3 years ago

Read 2 more answers

Suppose you are taking a walk one day when you see a tree branch snap at its base and begin to rotate downward with the break ne

Naya [18.7K]

Answer:

α = 3.27 rad/s²

Explanation:

Given that

L= 3 m

Lets take mass of tree = m kg

The torque to mass m = m g .L

The mass moment of inertia of tree ,I

I = mL² kg.m²

We know that

τ = I α

m g .L = mL² .α

α= g/L

Now by putting the value

$\alpha =\dfrac{ 9.81}{ 3}\ rad/s^2$

α = 3.27 rad/s²

No we can find the mass of the from the above information because angular acceleration is not depend on the mass of tree.

6 0

3 years ago

A point charge +6q is located at the origin, and a point charge -4q is located on the x-axis at D = 0.530 m. At what location on

belka [17]

Answer:

Explanation:

A point charge (+6q) at the origin I.e at (0,0)

Another point(-4q) charge is located at (0.53m, 0)

Both charges are on the x axis

Where will a third charge be place and it will experience no net force?

Fnet=0 due to charge 3

The location of qo should be at positive x axis, beyond q2(-4q), so has to have a stable charges.

Let the distance of -4q from qo be x

Then from +6q to qo is 0.56+x

The third charge has a charge of q.

Now we need to find Fnet due to charge 3.

Fnet= F13+F23

Let find F13

Let the distance of q1 from charge qo is 0.56+x

Both q1 and q3 are positive, there will be a force of repulsion between them, the F13 will be in the direction of positive x axis

F13=kq1q3/r²

q1= +6q and q3=q

F13=k6qq/(0.56+x)²

F13=k6q²/(0.56+x)²

In vector form

F13=k6q²/(0.56+x)² i

Now let find F23

q2 is negative and q3 is positive, a force or attraction will occur between the two bodies, then the F23 will move in the negative direction of x-axis

Given that, q2=(-4q) and q3=q, r=x

F23=kq1q3/r²

q1= +6q and q3=q

F23=k4qq/x²

F23=k4q²/x²

In vector form

F23=—k4q²/x² i

So, Fnet=F23+F13

Fnet= —k4q²/x²i + k6q²/(0.56+x)² i

Since Fnet=0

Then,

O=—k4q²/x² + k6q²/(0.56+x)²

k4q²/x² = k6q²/(0.56+x)²

Divide through by k2q², then we have

2/x²=3/(0.56+x)²

2(0.56+x)²=3x²

2(0.3136+1.12x+x²)=3x²

0.6272+2.24x+2x²=3x²

3x²-2x²-0.6272-2.24x=0

x²—2.24x—0.6272=0

Using formula method

a =1 b=-2.24 and x=-0.6272

x=-b±sqrt(b²-4ac)/2a

x=2.24±sqrt(-2.24²-4×1×-0.6272)/2×1

x=2.24±sqrt(5.0176+2.5088)/2

x=2.24±sqrt(7.5264)/2

x=(2.24±2.74)/2

Then x=(2.24+2.74)/2

x=2.49

or x=(2.24-2.74)/2

x=-0.25

So, x will be at (0.53+x) from the origin

1. When x =2.49

(0.53+2.49)=3.02m

2. When x =-0.25

This will not be possible because it will be attracted by the charges.

x=-0.25+0.53

x=0.28m

7 0

4 years ago

A toy car accelerates from 3m/s to 5m/s in 5sec . what is the acceleration

san4es73 [151]

Answer:

0.4

Explanation:

Because 3m/s is the initial velocity(u) and 5m/s is the final velocity(v) and time is 5 sec.

So, acceleration = v-u ÷ t

I'm confused

7 0

3 years ago