A two carbon chain attached to a benzene ring: ethylbenzene
Answer:
0.583 kilojoules
Explanation:
The amount of heat required to pop a single kernel can be calculated using the formula as follows:
Q = m × c × ∆T
Where;
Q = amount of heat (J)
m = mass of water (g)
c = specific heat capacity of water (4.184 J/g°C)
∆T = change in temperature
From the given information, m = 0.905 g, initial temperature (room temperature) = 21°C , final temperature = 175°C, Q = ?
Q = m × c × ∆T
Q = 0.905 × 4.184 × (175°C - 21°C)
Q = 3.786 × 154
Q = 583.044 Joules
In kilojoules i.e. we divide by 1000, the amount of heat is:
= 583.04/1000
= 0.583 kilojoules
Answer:
2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.
Explanation:
The balanced reaction is:
4 Fe + 3 O₂ → 2 Fe₂O₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- Fe: 4 moles
- O₂: 3 moles
- Fe₂O3: 2 moles
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
You can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe reacts with 3 moles of O₂, how much moles of Fe will be needed if 4.7 moles of O₂ react?
moles of O₂= 6.27
But 6.27 moles of Fe are not available, 5.4 moles are available. Since you have less moles than you need to react with 4.7 moles of O₂, iron Fe will be the limiting reagent.
So you can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe produce 2 moles of Fe₂O₃, how many moles of Fe₂O₃ will be produced if 5.4 moles of Fe react?
moles of Fe₂O₃= 2.7 moles
Then:
<u><em>2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.</em></u>
<span>It exhibits the Tyndall effect. ---> FALSE. IT BELONGS TO THE COLLOIDES.
Brownian motion is not visible in it.--> FALSE. IT IS A PROPERTY OF FLUIDS WHEN MICROSCOPICAL PARTICLES ARE IN IT.
It cannot be separated using filtration.--->TRUE. THE PARTICLES CANNOT BE DISTINGUISHED NOR SEPARATED BY FILTRATION.
It has at least two phases.-->FALSE. E.G. SALT IN WATER FORM ONE UNIQUE PHASE.</span>
Answer:
Tube 2: 8.26 * 10^-3; Tube 4: 6.83 * 10^-5
Explanation:
In the serial dilutions for MIC test, the volume of nutrient broth in each tube should be equal: 5.0 mL. And the volume of agent in each dilution should also be similar: 0.5 mL.
The serial dilutions was as following:
- Tube 1: 0.5/5.5
- Tube 2: 0.5 mL of tube 1 was diluted with 5.0 mL broth. Then, the dilution of tube 2 is (1:11) * (1:11) = (0.5/5.5) * (0.5/5.5) = 1:121 = 8.26 * 10^-3
- Tube 3: We perform the similar calculation. Thus, the result is 1:1331 = 7.51 * 10^-4
- Tube 4: It is 1:14641 = 6.83 * 10^-5.
