1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Klio2033 [76]
4 years ago
15

30 POINTS! ----- How many moles of oxygen gas are needed to completely react with 145 grams of aluminum? Report your answer with

3 significant figures. ____ mole O2.
Chemistry
1 answer:
gladu [14]4 years ago
4 0
First a balanced reaction equation must be established:
4Al _{(s)}    +   3 O_{2}  _{(g)}     →    2 Al_{2} O_{3}

Now if mass of aluminum = 145 g
the moles of aluminum = (MASS) ÷ (MOLAR MASS) = 145 g ÷ 30 g/mol
                                                                                    =  4.83 mols

Now the mole ratio of Al : O₂ based on the equation is  4 : 3  
                                                                [4Al  + 3 O₂ → 2 Al₂O₃]

∴ if moles of Al = 4.83 moles
  then moles of O₂ = (4.83 mol ÷ 4) × 3
                              =  3.63 mol   (to  2 sig. fig.) 

Thus it can be concluded that 3.63 moles of oxygen is needed to react completely with 145 g of aluminum. 


     
You might be interested in
Please help ASAP 29 points Which individual elements make up the
Inessa [10]
Calcium carbon oxygen, calcium chlorine , carbon hydrogen oxygen, hydrogen chlorine, calcium oxygen hydrogen. pretty sure they’re right
5 0
3 years ago
Read 2 more answers
Which action is necessary for a solar eclipse to occur?​
Nat2105 [25]

Answer:

Moon has to be in-between the Earth and the Sun.

2. Moon's umbra should sweep your place.

3. Latitude and longitude of your place should be within the befitting limits.

6 0
3 years ago
Atomic emission spectra are produced when the light emitted by an element passes through a prism. Which of the following stateme
xenn [34]
Option C: elements produce spectra with only few distinct lines.

The spectra are not continuos and are different for every element. This permits to identify elements.
3 0
3 years ago
from the following equation in which decomposition of CaCO3 takes place, give your justification. CaCO3 gives Ca +CO2 ​
IceJOKER [234]

Answer:

CaCO₃(s) => CaO(s) + CO₂(g) ... GpIIA Decomp

Explanation:

Metallic Carbonates decompose into a metallic oxide and carbon dioxide.

Examples:

Na₂CO₃(s) => Na₂O(s) + CO₂(g) ... GpIA Decomp

MgCO₃(s) => MgO(s) + CO₂(g) ... GpIIA Decomp

7 0
3 years ago
Balance this equation: Al+ HNO3 ---- H2 + Al(NO3)3​
romanna [79]

Answer:

2Al+ 6HNO3 ---- 3H2 + 2Al(NO3)3​

Explanation:

Put coefficient a,b,c, and d for calculation:

a Al + b HNO3 = c H2 + d Al(NO3)3

for Al: a = d

for H: b = 2c

for N: b = 3d

for O: 3b = 9d

Suppose a=1, then d=1, b=3, c=3/2

multiply 2 to make all natural number, a=2, then b=6, c=3, d=2

6 0
3 years ago
Other questions:
  • The best lewis structure for sulfuric acid has zero formal charges, sulfur as the central atom, and no bonds between s and h. ho
    11·2 answers
  • In a candy factory, the nutty chocolate bars contain 25.0 % pecans by mass. If 5.0 kg of pecans were used for candy last Tuesday
    8·1 answer
  • What is the law of redox reactions?
    7·1 answer
  • . Through what three mechanisms do gamma rays interact with matter?
    7·1 answer
  • Determine the net change in NADHNADH , FADH2FADH2 , and GTPGTP from the passage of two acetyl-SCoA molecules through the citric
    15·1 answer
  • Does anyone know how to write out the formula for these?? not just the answer x
    9·1 answer
  • On the lewis dot diagram What element reacts simiar to clorine
    14·1 answer
  • 28. Element X is powerful enough to reduce sodium ions to sodium metal. Barium is a strong enough reducing agent to reduce X +to
    7·1 answer
  • If a horse gallops 1 meter per second, how far can it travel in 1 minute? <br><br> pls help
    5·1 answer
  • An oxide of nitrogen contains 30.45 mass % N.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!