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romanna [79]
3 years ago
6

A primary amine contains a five-membered carbon ring. The degree of unsaturation for the five-membered carbon ring is equal to t

hree. In the chemical formula, there are seven carbon atoms. Determine its chemical formula.
Chemistry
1 answer:
IceJOKER [234]3 years ago
7 0

Answer:

C₇H₁₁N

Explanation:

To find the chemical formula, first, let's evaluate the given conditions.

1. <u>Is a primary amine</u>:

This means that the amine is connected to a carbon, like NH₂-R

2. <u>The degree of unsaturation of the five-membered carbon ring is equal to three</u>:

One of the degrees of unsaturation is for the five-membered carbon ring, the other two are for pi-bonds. This means that the five-membered carbon ring has 2 pi-bonds inside.

3. <u>There are seven carbon atoms</u>:

Five of these seven carbons are for the carbon ring and the other two are bonded to the primary amine.

From all of the above, we have that the chemical formula is:

C₅H₅-C₂H₄-NH₂ = C₇H₁₁N  

I hope it helps you!

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Explanation:

P1V1 = P2V2

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a concentration solution of H2so4 is 59.4% by mass (m/m) and has a density of 1.83 g/mL. How many mL of the solution would be re
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Answer: 41.5 mL

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

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Given : 59.4 g of H_2SO_4 in 100 g of solution  

moles of H_2SO_4=\frac{\text {given mass}}{\text {molar mass}}=\frac{59.4g}{98g/mol}=0.61

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Now put all the given values in the formula of molality, we get

Molality=\frac{0.61\times 1000}{54.6ml}=11.2M

To calculate the volume of acid, we use the equation given by neutralisation reaction:

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M_1\text{ and }V_1 are the molarity and volume of stock acid which is H_2SO_4

M_2\text{ and }V_2 are the molarity and volume of dilute acid which is H_2SO_4

We are given:

M_1=11.2M\\V_1=mL\\M_2=0.30M\\V_2=1550mL

Putting values in above equation, we get:

11.2\times V_1=0.30\times 1550\\\\V_1=41.5mL

Thus 41.5 mL of the solution would be required to prepare 1550 mL of a .30M solution of the acid

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