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3 years ago

7

In geometric progression, the ratio of each number to the preceding one is the same. Which is an example of a geometric progress

ion?
A. 4, 12, 36

B. 3, 21, 35

C. 1, 2, 3

D. 4, 6, 8

2 answers:

devlian [24]3 years ago

7 0

It would be A because this sequence has a factor of 2 between each number

Svet_ta [14]3 years ago

3 0

The answer is A.

Because geometric progression refers to sequence that a multiplication relationship between them.
$4 \times 3 = 12 \\ 12 \times 3 = 36$
The common ratio is 3

Hope this helps. - M

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Which is the intersection of the sets {0, 1, 5, 7, 8} and {0, 5, 7, 9}?

MrRissso [65]

The intersection of the steps is just a fancy way of asking wi\hich numbers are in both equations so lets look and see :)

The 1st = 0...1...5...7...8
The 2nd =0........5...7........9
Answer = D {0, 5, 7}
Hope this helps have any questions let me know :)

6 0

3 years ago

Can someone plz help me with math?? theres only 3 parts!!!

vovikov84 [41]

To find the volume of each prism, you will multiply the length by the width by the height.

V = lwh
3 3/4 x 3 x 3 1/4
V = 36 9/16 cubic feet

V = lwh
1/4 x 1/4 x 1/4
V= 1/64 cubic feet

Both boxes are similar in that they can be described as a rectangular prism.

They are different because one prism has congruent edges, so we call it a cube. The other one has varying side lengths, therefore it is only a rectangular prism.

3 0

3 years ago

Read 2 more answers

If you travel at a rate of 45 miles per hour, how many minutes will it take you to travel 1 mile

gavmur [86]

1 minute and 15 seconds.

8 0

2 years ago

Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2

Verdich [7]

Answer:

(a) $f'(x)=-\frac{2}{x^3}$

(b) $y=-0.25x+0.75$

Step-by-step explanation:

The given function is

$f(x)=\frac{1}{x^2}$ .... (1)

According to the first principle of the derivative,

$f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}$

Cancel out common factors.

$f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}$

By applying limit, we get

$f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}$

$f'(x)=\frac{-2x)}{x^4}$

$f'(x)=\frac{-2)}{x^3}$ .... (2)

Therefore $f'(x)=-\frac{2}{x^3}$ .

(b)

Put x=2, to find the y-coordinate of point of tangency.

$f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25$

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

$m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}$

Substitute x=2 in equation 2.

$f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25$

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

$y-y_1=m(x-x_1)$

$y-0.25=-0.25(x-2)$

$y-0.25=-0.25x+0.5$

$y=-0.25x+0.5+0.25$

$y=-0.25x+0.75$

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0

3 years ago

1b) Answer the following: *<br> If arc WX = 40' and arc Y Z = 92, find m23.

spin [16.1K]

Answer:

m<3 = 66°

Step-by-step explanation:

<3 is an angle with its vertex inside the circle shown in the diagram. This, it's an internal angle.

The measure of an internal angle is equal to half the sum of the measure of the arcs intercepted.

Thus, the equation that shows relationship between <3 and arc WX and arc YZ is shown below:

m<3 = ½(40 + 92)

m<3 = ½(132)

m<3 = 66°

5 0

3 years ago