Answer:
Explanation:
It is given that,
The radius of the solid sphere, R = 50 cm = 0.5 m
Charge on the sphere,
We need to find the magnitude of the electric field r = 10.0 cm away from the center of the sphere. The electric field at point r away form the center of the sphere is given by :
So, the electric field 10.0 cm away from the center of the sphere is . Hence, this is the required solution.
Because of friction, net work on the crate is less. ∆KE = Net work = net force x distance = (100 N – 70 N)(10 m) = 300 J.
Explanation:
It is given that,
Distance between the slits, d = 5 mm = 0.005 m
Distance between slit and screen, D = 1.4 m
For m = 2, and
For m = 2, and
Separation between two fringes is :
Hence, this is the required solution.
<u>Answer:</u>
Mass of combined products = 20.4 grams
Mass of combined product and Erlenmeyer flask = 136 grams
<u>Explanation:</u>
By law of mass conservation, mass cannot be destroyed or created. So mass before reaction is mass after reaction.
Mass of lead(II) nitrate = 15.6 grams
Mass of potassium iodide = 4.8 grams
Mass of the Erlenmeyer flask = 115.6 grams
Mass of reactants = 15.6 + 4.8 = 20.4 grams
So mass of products = 20.4 grams
Mass of combined product and Erlenmeyer flask = 115.6 + 20.4 = 136 grams