Answer:
The store energy in the inductor is 0.088 J
Explanation:
Given that,
Inductor = 100 mH
Resistance = 6.0 Ω
Voltage = 12 V
Internal resistance = 3.0 Ω
We need to calculate the current
Using ohm's law
![V = IR](https://tex.z-dn.net/?f=V%20%3D%20IR)
![I=\dfrac{V}{R+r}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7BV%7D%7BR%2Br%7D)
Put the value into the formula
![I=\dfrac{12}{6.0+3.0}](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7B12%7D%7B6.0%2B3.0%7D)
![I=1.33\ A](https://tex.z-dn.net/?f=I%3D1.33%5C%20A)
We need to calculate the store energy in the inductor
![U=\dfrac{1}{2}LI^2](https://tex.z-dn.net/?f=U%3D%5Cdfrac%7B1%7D%7B2%7DLI%5E2)
![U=\dfrac{1}{2}\times100\times10^{-3}\times(1.33)^2](https://tex.z-dn.net/?f=U%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes100%5Ctimes10%5E%7B-3%7D%5Ctimes%281.33%29%5E2)
![U=0.088\ J](https://tex.z-dn.net/?f=U%3D0.088%5C%20J)
Hence, The store energy in the inductor is 0.088 J
Explanation:
Minimum of aerobic activity 150 minutes, or a mix of moderates and intensive exercise 75 minutes of vigorous aerobic activity a week. We can extend this practice throughout the week with the instructions. Mild aerobic workouts might include practices like quick strolling or swimming, while activity like running can include strong aerobic activity.
Answer:
3.80 m/s
Explanation:
Solution: From the question we have:
A 2.10 x 10^3 kg car starts from rest at the top of a 5.0 m long driveway that is sloped at 20 degrees with the horizontal.
average friction force of 4.0 x 10^3 N impedes the motion
To find out: find the speed of the car at the bottom of the driveway.
=>h = 5×sin20 = 1.71 m.
PE = mgh = 2100×9.8×1.71 = 35,192 J.
KE = PE-work done by frictional force
KE=PE-4000×5
0.5mV^2 = 35192 - 4000×5
1050V^2 = 15,192
V^2 = 14.47
V = 3.80 m/s.