His total displacement from his original position is -1 m
We know that total displacement of an object from a position x to a position x', d = final position - initial position.
d = x' - x
If we assume the lad's initial position in front of her house is x = 0 m. The lad then moves towards the positive x-axis, 5 m. He then ends up at x' = 5 m. He then finally goes back 6 m.
Since displacement = final position - initial position, and his displacement is d' = -6 m (since he moves in the negative x - direction or moves back) from his initial position of x' = 5 m.
His final position, x" after moving back 6 m is gotten from
x" - x' = -6 m
x" = -6 + x'
x" = -6 + 5
x" = -1 m
Thus, his total displacement from his original position is
d = final position - initial position
d = x" - x
d = -1 m - 0 m
d = -1 m
So, his total displacement from his original position is -1 m
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Answer:
(a) Most reactive
Metal B
Metal D
Metal A
Least reactive
Metal C
(b) (i) Bubbles should form very slowly
(ii) No reaction takes place
Explanation:
(a) The given metals arranged in their order of reactivity are;
Most reactive
Metal B
Metal D
Metal A
Least reactive
Metal C
The other of reactivity is based on the nature of their reactivity of the metals in air
(b) (i) Based on the reactivity of the metals in air, whereby metal A reacts very slowly and an oxide is formed, we have that, based on the reactivity of the metal A, when mixed with dilute hydrochloric acid, bubbles should form very slowly
(ii) Similarly, given that metal C is unreactive, we have that when small pieces of metal C are added to dilute hydrochloric acid, no reaction takes place.
Answer:
Explanation:
We shall apply law of conservation of momentum .
total Initial momentum =
7.5 x 8.85 = 66.375 kg m / s
total mass = 7.5 + 61.5 = 69 kg , common velocity of ball and performer be v
Total momentum = 69 v
69 v = 66.375
v = 66.375 / 69
= .962 m /s .
Answer:
58.5 deg
Explanation:
= mass of the pig toy = 0.30 kg
= speed of the toy = 2 m/s
= radius of the circle = 0.25 m
= Angle of the string with the vertical = ?
= Tension force in the string
Using equilibrium of force in vertical direction
eq-1
Along the horizontal direction, the component of tension force provides the necessary centripetal force, hence
eq-2
Dividing eq-2 by eq-1




= 58.5 deg
Answer:
22
Explanation:
all the resistance numbers added together 2.0+6.0+10.0+4.0
<em>resistance</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em>u</em><em>l</em><em>a</em><em> </em><em>:</em><em> </em><em>v</em><em> </em><em>be</em><em>t</em><em>t</em><em>a</em><em>r</em><em>y</em><em> </em><em>=</em><em> </em><em>v</em><em>1</em><em> </em>+ <em>v</em><em>2</em><em> </em><em>+</em><em> </em><em>v</em><em>3</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em>