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Levart [38]
2 years ago
8

A hilly road is spiral in shape.​

Physics
1 answer:
Llana [10]2 years ago
6 0
I- wym incorrect answer i-
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Which statement about an object in motion is correct? <br> Help
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2 years ago
The state of matter that has low thermal expansion​
leonid [27]

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Matter

Explanation:

Because it is solid

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Physics question!!!
lesantik [10]

Answer:

4.5 metres

Explanation:

Using Hooke's Law (F\propto x)

We need to find the spring constant of the bungee cord with the given extension and force, we can do this by substituting in known values.

600=3k\\k=200

Now we have found the spring constant of the bungee cord, we can substitute it in for the a different force. As the cord is the same we can use the same spring constant.

900=200x\\x=4.5

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3 years ago
You're collecting data in BeyondLabz for an object in free fall, subject to air resistance. How do you know when you've collecte
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Enough data points would have been collected when specific data for upward and downward motion are collected.

<h3>What is a Data point?</h3>

A data point is a discrete unit of information. This information is always unique.

<h3>Free fall</h3>

An object subjected to free fall is under the influence of gravity. An object subjected has different time of motion for upward and downward motion.

Thus, we can conclude that enough data points would have been collected when specific data for upward and downward motion are collected.

Learn more about free fall here: brainly.com/question/10909077

6 0
2 years ago
A copper wire has a radius of 3.5 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends o
denpristay [2]

Answer:

The tensile stress on the wire is 550 MPa.

Explanation:

Given;

Radius of copper wire, R = 3.5 mm

extension of the copper wire, e =  5.0×10⁻³ L

L is the original length of the copper wire,

Young's modulus for copper, Y =  11×10¹⁰Pa.

Young's modulus, Y is given as the ratio of tensile stress to tensile strain, measured in the same unit as Young's modulus.

Y =\frac{Tensile \ stress}{Tensile \ strain} \\\\Tensile \ stress = Y*Tensile \ strain\\\\But, Tensile \ strain = \frac{extension}{original \ Length} = \frac{5.0*10^{-3} L}{L} = 5.0*10^{-3}\\\\Tensile \ stress = 11*10^{10} *5.0*10^{-3} \ = 550*10^6 \ Pa

Therefore, the tensile stress on the wire is 550 MPa.

8 0
3 years ago
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