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Goshia [24]
3 years ago
5

What measure of center would you use for a bimodal histogram? and why?

Mathematics
2 answers:
ELEN [110]3 years ago
6 0

Answer:

Unless you have a good reason to use mode or median, like bimodal distributions or heavily skewed data, the best measure to use is the mean. SPSS Tips: Vocabulary: Measures of Central Tendency - Numbers that represent the average or typical score obtained from measurements of a sample.

mojhsa [17]3 years ago
5 0

<u>Mean and median both try to measure the "central tendency" in a data set. The goal of each is to get an idea of a "typical" value in the data set. The mean is commonly used, but sometimes the median is preferred.</u>

<u>pls </u><u>mark</u><u> as</u><u> brainlist</u><u> ☺️</u>

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Nuetrik [128]
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3 years ago
Can somebody help me with this please?
Svetach [21]
Multiply both sides by -4/7
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3 years ago
Ok need help this is the question :Use the Pythagorean theorem to write an equation for the distance Jane's trainer bikes.
IRINA_888 [86]

Answer:

<em>Jane traveled 8 miles farther then her trainer</em>

Step-by-step explanation:

<u>The Pythagora's Theorem</u>

In any right triangle, the square of the measure of the hypotenuse is the sum of the squares of the legs. This can be expressed with the formula:

c^2=a^2+b^2

Where

c = Hypotenuse or largest side

a,b = Legs or shorter sides

Jane's path from the Health Club to the end of her route describes two sides of a right triangle of lengths a=16 miles and b=12 miles.

Her total distance traveled is 16 + 12 = 28 miles

Her trainer goes directly from the Health Club to meet her through the hypotenuse of the triangle formed in the path.

We can calculate the length of his route as:

c=\sqrt{16^2+12^2}

c=\sqrt{256+144}=\sqrt{400}=20

c = 20 miles

The difference between their traveled lengths is 28 - 20 = 8 miles

Jane traveled 8 miles farther then her trainer

8 0
3 years ago
Please can some explain how to identify angles that on the same segment? ​
sp2606 [1]

Step-by-step explanation:

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Picture 1  a° = a°  they are the same

Picture 2  p= 52°  q= 40° Angles in the same segment are equal. if they ask you to calculate you just show both angles p= 52 and q=40.

Picture 3 + 4  Let the obtuse angle MOQ = 2x.  

Using the circle theorem, the angle at the centre is twice   the angle at the circumference.

Therefore picture 4 tells us and proves;

Angle MNQ = x and angle MPQ = x.

Picture 5

A cyclic quadrilateral is a quadrilateral drawn inside a circle. Every corner of the quadrilateral must touch the circumference of the circle.

The second shape is not a cyclic quadrilateral. One corner does not touch the circumference.

Picture 6

The opposite angles in a cyclic quadrilateral add up to 180°.

a + c = 180°

b + d = 180°

Picture 7

Example

Calculate the angles a and b.

The opposite angles in a cyclic quadrilateral add up to 180°.

This is a picture that couldn't be added but has a quadrilateral occupying half the triangle consisting of 3 arcs the middle one was 140 and proved part of one triangle. The x (a) missing angle showed below a = 180-60 = 120 °

So hopefully this will help you remember the format here for quadrilateral shapes within a circle.

b = 180 - 140 = 40°

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Answer:

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Step-by-step explanation:

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