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Goshia [24]
3 years ago
5

What measure of center would you use for a bimodal histogram? and why?

Mathematics
2 answers:
ELEN [110]3 years ago
6 0

Answer:

Unless you have a good reason to use mode or median, like bimodal distributions or heavily skewed data, the best measure to use is the mean. SPSS Tips: Vocabulary: Measures of Central Tendency - Numbers that represent the average or typical score obtained from measurements of a sample.

mojhsa [17]3 years ago
5 0

<u>Mean and median both try to measure the "central tendency" in a data set. The goal of each is to get an idea of a "typical" value in the data set. The mean is commonly used, but sometimes the median is preferred.</u>

<u>pls </u><u>mark</u><u> as</u><u> brainlist</u><u> ☺️</u>

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I believe you are referring to the half-life formula, which is used to calculate the half-life (when the substance drops to half of its original amount) of radioactive substances.  The equation is as follows: A = P(.5)^{t/h}

<em>A</em> is the remaining amount
<em>P</em> is the initial amount
<em>t</em> is the time that has passed
<em>h</em> is the half-life of the substance

When plugging values into the equation, make sure that <em>t </em>and <em>h </em>are both measured in the same unit (e.g. <em>t </em>days and <em>h </em>days), as well as <em>A </em>and <em>P</em>.
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3 years ago
Heather purchased a new $1,500 laptop by using a credit card with a 17% interest rate. She will pay off the balance in 2 years b
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Step-by-step explanation:

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3 years ago
3(3a+2)+6=30 what does a equal
Naya [18.7K]

Answer:

a=2

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
A cell phone provider classifies its customers as Low users (less than 400 minutesper month) or High users (400 or more minutes
Svet_ta [14]

Answer:

a ) See step by step explanation

b) 50%   and  50%

Step-by-step explanation:

The definition of type of user x is:

if x < 400 minutes  per month  low user

if x > 400 minutes per month  high user

The value for these states are of course yes  or no  ( the user is low or high user)

Then:

if the user is low today  xt  (0)    we have the probability of 80% ( 0,8) of have the user in the same condition and 20% (0,2) of having him or her as high user

xt = 1      

If the user is high today xt (1) is high today we have the probability of 70% ( 0,7) of having  the user in the same condition and 30% (0,3) of having him or her as high user

a) Then we construct the stochastic matrix

 Type of user

         (xt)               xt         xt+1  

      Low (0) or L   0,8        0,2

     High(1)  or H   0,3        0,7

The resulting equation system is:

xt  =  0,8* xt  +  0,2* xt+1

xt+1  = 0,3*xt + 0,7* xt+1

1  =  xt + xt+1

Solving for variables         xt+1  =  1  - xt

xt  = 0,8*xt + ( 1 - xt ) * 0,2

xt - 0,8*xt = 0,2 - 0,2xt

xt - 0,6*xt = 0,2

0,4*xt = 0,2

xt = 0,5       and     xt+1  = 0,5

b)  If in January 0,5  ( 50%) of customesr were  low user

In february  teh % of low user customer wll be

xt  =  0,8* xt  +  0,2* xt+1

0,5 = 0,8*0,5 + 0,2*xt+1

0,5 = 0,4 + 0,2 *xt+1

0,1/0,2 = xt+1        xt+1 = 0,5       or   50%

The same answer for March

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3 years ago
Explain how you used mental math
andriy [413]
Addition, I would use the principles of addition. 
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