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trasher [3.6K]
3 years ago
5

The electric potential in a particular region of space varies only as a function of y-position and is given by the function V(y)

1.69y2 +15.6y 52.5) Volts. Calculate the magnitude of the electric field at the position y - 22.5 meters
Physics
1 answer:
nikdorinn [45]3 years ago
3 0

Answer:

E = 55.9583\ Volts/meter

Explanation:

First let's find the electric potential using y = 22.5:

V(y) = 1.69y^2 +15.6y+52.5

V(22.5) = 1.69(22.5)^2 + 15.6*22.5 + 52.5

V(22.5) = 1259.0625\ Volts

Then, to find the magnitude of the electric field, we just need to divide the electric potential by the distance y:

E = V/d

E = 1259.0625/22.5

E = 55.9583\ Volts/meter

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