Question

The electric potential in a particular region of space varies only as a function of y-position and is given by the function V(y)1.69y2 +15.6y 52.5) Volts. Calculate the magnitude of the electric field at the position y - 22.5 meters

Answer 1

Answer:

$E = 55.9583\ Volts/meter$

Explanation:

First let's find the electric potential using y = 22.5:

$V(y) = 1.69y^2 +15.6y+52.5$

$V(22.5) = 1.69(22.5)^2 + 15.6*22.5 + 52.5$

$V(22.5) = 1259.0625\ Volts$

Then, to find the magnitude of the electric field, we just need to divide the electric potential by the distance y:

$E = V/d$

$E = 1259.0625/22.5$

$E = 55.9583\ Volts/meter$