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3 years ago

Since the particles of liquids are able to slide past each other into different locations they have ______.

Physics

1 answer:

amid [387]3 years ago

7 0

C Bc it’s the right answers not wrong

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A small 17 kilogram canoe is floating downriver at a speed of 3 m/s. What is the canoe's kinetic energy?

aksik [14]

KE=1/2mv^2

So from the given information me can plug in the values and find the KE or Kinetic Energy for the canoe;

KE=1/2(17kg)(3m/s)^2
KE=8.5kg*9m^2s^2= 76.5J of Kinetic Energy

Hope this helps, any questions please just ask. Thank you.

7 0

4 years ago

Read 2 more answers

In the one pully system when you move the mass from the 20 cm mark to the 15 cm mark, it moves 5 cm. How far did you pull the st

drek231 [11]

Answer:

5 cm

Explanation:

4 0

3 years ago

Which layer of ground contain organic matter and tiny rock particles

Bogdan [553]

A cuz the soil wi;l have the most tiny rock particularly i think feel free to ask any questions marked brailiest would be appreciated

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3 years ago

An electron collides elastically with a stationary hydrogen atom. The mass of the hydrogen atom is 1837 times that of the electr

tamaranim1 [39]

Answer:

$\frac{K_{h}}{K_{i}} = = 2.17 \times 10^{-3}$

Explanation:

As we know that there is no external force on the system of hydrogen atom and electron so we will say momentum is conserved

so we will have

$m_1 v_{1i} = m_1v_{1f} + m_2v_{2f}$

here we know that

$m_1 = m$

$m_2 = 1837m$

now we have

$m v = mv_{1f} + 1837v_{2f}$

$v_{1f} + 1837v_{2f} = v$

also we know that

$v_{2f} - v_{1f} = v$

now we will have

$1838v_{2f} = 2v$

$v_{2f} = \frac{v}{919}$

now we need to find the ratio of kinetic energy of hydrogen atom with initial kinetic energy

so it is given as

$\frac{K_{h}}{K_{i}} = \frac{\frac{1}{2}(1837m)(\frac{v}{919})^2}{\frac{1}{2}mv^2}$

$\frac{K_{h}}{K_{i}} =\frac{1837}{919^2}$

$\frac{K_{h}}{K_{i}} = = 2.17 \times 10^{-3}$

4 0

4 years ago

The brightest, hottest, an

dangina [55]

The speed of the star is 255 km/s

Explanation:

The kinetic energy of a body is the energy possessed by the body due to its motion. Mathematically:

$KE=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

For the star in this problem, we have:

$m=3.38\cdot 10^{31} kg$ is the mass

$KE=1.10\cdot 10^{42} J$ is the kinetic energy

Therefore, the speed of the star is:

$v=\sqrt{\frac{2KE}{m}}=\sqrt{\frac{2(1.10\cdot 10^{42})}{3.38\cdot 10^{31}}}=2.55\cdot 10^5 m/s$

Which corresponds to 255 km/s

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

6 0

3 years ago