Answer: magnitude of applied force is FA = mg + F
Where F is the resultant force downward that the rope moves with
Explanation:
Force downwards F is,
F = FA - T
T is the upwards tension force on the rope
FA is the actual applied force in pulling the rope down.
Therefore, T = FA - F .....equ. (1)
For the box to move up with force ma ( it's mass times its acceleration upwards) upwards tension on the roap must exceed its own weight mg ( it's mass times acceleration due to gravity 9.8m/s^2)
Therefore, ma = T - mg
T = ma + mg ..... equ. (2)
Equating equ. 1 and 2
T = FA - F = ma + mg
Therefore FA = ma + mg + F
But at constant velocity a = 0
Magnitude of applied force becomes
FA = mg + F
See image below
Answer:
The center of mass of the Earth-Moon system is 4.673 kilometers away from center of Earth.
Explanation:
Let suppose that planet and satellite can be treated as particles. The masses of Earth and Moon (
,
) are
and
, respectively. The distance between centers is 384,403 kilometers. The location of the center of mass can be found by using weighted averages:
![\bar x = \frac{x_{E}\cdot m_{E}+x_{M}\cdot m_{M}}{m_{E}+m_{M}}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7Bx_%7BE%7D%5Ccdot%20m_%7BE%7D%2Bx_%7BM%7D%5Ccdot%20m_%7BM%7D%7D%7Bm_%7BE%7D%2Bm_%7BM%7D%7D)
If
and
, then:
![\bar x = \frac{(0\,km)\cdot (5.972\times 10^{24}\,kg)+(384,403\,km)\cdot (7.349\times 10^{22}\,kg)}{5.972\times 10^{24}\,kg+7.349\times 10^{22}\,kg}](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%20%5Cfrac%7B%280%5C%2Ckm%29%5Ccdot%20%285.972%5Ctimes%2010%5E%7B24%7D%5C%2Ckg%29%2B%28384%2C403%5C%2Ckm%29%5Ccdot%20%287.349%5Ctimes%2010%5E%7B22%7D%5C%2Ckg%29%7D%7B5.972%5Ctimes%2010%5E%7B24%7D%5C%2Ckg%2B7.349%5Ctimes%2010%5E%7B22%7D%5C%2Ckg%7D)
![\bar x = 4.673\,km](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%204.673%5C%2Ckm)
The center of mass of the Earth-Moon system is 4.673 kilometers away from center of Earth.
The sun is abiotic-Brainly.com
Answer:
f₂ = 468.67 Hz
Explanation:
A beat is a sudden increase and decrease of sound. The beats are produced through the interference of two sound waves of slightly different frequencies. Now we have the following data:
The higher frequency tone = f₁ = 470 Hz
No. of beats = n = 4 beats
Time period = t = 3 s
The lower frequency note = Frequency of Friend's Trombone = f₂ = ?
Beat Frequency = fb
So, the formula for beats per second or beat frequency is given as:
fb = n/t
fb = 4 beats/ 3 s
fb = 1.33 Hz
Another formula for beat frequency is:
fb = f₁ - f₂
f₂ = f₁ - fb
f₂ = 470 Hz - 1.33 Hz
<u>f₂ = 468.67 Hz</u>
<span>The regioin is titled towqrd the Sun during polar day. (C)
(The same exact thing happens in areas south of the Antarctic Circle
in the southern hemisphere. The only difference is that the whole thing
is spelled better in the South.)</span>