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ivanzaharov [21]
3 years ago
13

Where do the magnetic fields of atoms line up

Physics
2 answers:
SIZIF [17.4K]3 years ago
6 0

Magnetic field of atoms lines up in North-South direction. Magnetic feild is strongest at both end/pole. (North pole and south pole). The atom between the line are weaker than the one at ends.

Mariana [72]3 years ago
6 0

Answer:

usally up  on north side

Explanation:

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When the rubber sheet is pulled down, the volume of the bell jar is ____________ and the pressure in the bell jar is ___________
Makovka662 [10]

Answer:

increases, decreases, respiration

8 0
2 years ago
Explain what makes up a circuit .
ANEK [815]

Explanation:

An electrical circuit needs:

a source of electrical power (this could be a power plant or a battery)

a material along which the electricity can flow (this may be a copper wire)

something to power (this could be a bulb)

The circuit is connected in a loop. Then, the source of power pushes electrons around the wire. It lights the bulb and continues in the circuit until it is broken.

A simple circuit lights one bulb. More difficult circuits might have several switches and loops. This would allow different groups of lights to be turned on or off at the same time.

( I hope this was helpful) >;D

Read more: All in a Circuit - What Makes a Circuit?, Battery Power, How a Battery Works, Flat!, Home Circuits, Conductors and Insulators - JRank Articles https://science.jrank.org/kids/pages/232/All-in-Circuit.html#ixzz6qWd5gxGf

5 0
3 years ago
What area must the plates of a capacitor be if they have a charge of 5.7uC and an electric field of 3.1 kV/mm between them? O 0.
kirill [66]

Answer:

Area of the plates of a capacitor, A = 0.208 m²

Explanation:

It is given that,

Charge on the parallel plate capacitor, q = 5.7\ \mu C=5.7\times 10^{-6}\ C

Electric field, E = 3.1 kV/mm = 3100000 V/m

The electric field of a parallel plates capacitor is given by :

E=\dfrac{q}{A\epsilon_o}

A=\dfrac{q}{E\epsilon_o}

A=\dfrac{5.7\times 10^{-6}\ C}{3100000\ V/m\times 8.85\times 10^{-12}\ F/m}

A = 0.208 m²

So, the area of the plates of a capacitor is 0.208 m². Hence, this is the required solution.

8 0
3 years ago
A wave with an amplitude of 9.3 mm is traveling along a string whose linear mass density is 230 g/m and whose tension is 65 N. I
dsp73

Answer:

The rate of transfer of energy is equal to 23.76W or 23.76J/s as may be required both forms are correct. The physical quantities needed to calculate the rate of energy transfer are the linear mass density or mass per unit length, tension force, amplitude, angular frequency( which is equal to 2pi •f )

Explanation:

The required quantity is the average power or average rate of energy transfer which differs from the maximum or instantaneous rate of energy transfer. The calculation steps to the answer above can be found in the attachment below. Should the requested quantity be the instantaneous quantity the answer will be 2 x Pav which equals 47.52W or 47.52J/s.

3 0
3 years ago
A point on the end of a tuning fork moves in simple harmonic motion described by d = a sin ωt. Find ω given that the tuning fork
pantera1 [17]

Answer:

1609.1429 rad/sec

Explanation:

By using the relation Angular velocity and frequency as:

Angular velocity (ω) = 2×π×Frequency (ν)

Given the frequency = 256 vibrations per second.

So, Angular velocity can be calculated by using the above formula as:

Angular velocity (ω) = 2×π×Frequency (ν)

⇒Angular velocity (ω) = 2×π×256 rad/ sec

⇒Angular velocity (ω) = 2×(22/7)×256 rad/ sec

<u>⇒Angular velocity (ω) = 1609.1429 rad/ sec</u>

5 0
3 years ago
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