Explanation:
An electrical circuit needs:
a source of electrical power (this could be a power plant or a battery)
a material along which the electricity can flow (this may be a copper wire)
something to power (this could be a bulb)
The circuit is connected in a loop. Then, the source of power pushes electrons around the wire. It lights the bulb and continues in the circuit until it is broken.
A simple circuit lights one bulb. More difficult circuits might have several switches and loops. This would allow different groups of lights to be turned on or off at the same time.
( I hope this was helpful) >;D
Read more: All in a Circuit - What Makes a Circuit?, Battery Power, How a Battery Works, Flat!, Home Circuits, Conductors and Insulators - JRank Articles https://science.jrank.org/kids/pages/232/All-in-Circuit.html#ixzz6qWd5gxGf
Answer:
Area of the plates of a capacitor, A = 0.208 m²
Explanation:
It is given that,
Charge on the parallel plate capacitor, 
Electric field, E = 3.1 kV/mm = 3100000 V/m
The electric field of a parallel plates capacitor is given by :



A = 0.208 m²
So, the area of the plates of a capacitor is 0.208 m². Hence, this is the required solution.
Answer:
The rate of transfer of energy is equal to 23.76W or 23.76J/s as may be required both forms are correct. The physical quantities needed to calculate the rate of energy transfer are the linear mass density or mass per unit length, tension force, amplitude, angular frequency( which is equal to 2pi •f )
Explanation:
The required quantity is the average power or average rate of energy transfer which differs from the maximum or instantaneous rate of energy transfer. The calculation steps to the answer above can be found in the attachment below. Should the requested quantity be the instantaneous quantity the answer will be 2 x Pav which equals 47.52W or 47.52J/s.
Answer:
1609.1429 rad/sec
Explanation:
By using the relation Angular velocity and frequency as:
Angular velocity (ω) = 2×π×Frequency (ν)
Given the frequency = 256 vibrations per second.
So, Angular velocity can be calculated by using the above formula as:
Angular velocity (ω) = 2×π×Frequency (ν)
⇒Angular velocity (ω) = 2×π×256 rad/ sec
⇒Angular velocity (ω) = 2×(22/7)×256 rad/ sec
<u>⇒Angular velocity (ω) = 1609.1429 rad/ sec</u>