The hotter molecules become, the faster they move around. The colder they are, the more slow and lethargic they are
A. True
Hope this helps :)
This study was aimed at testing the construct validity of the basketball basic motion skills test instrument (ITK GDBB). The research used descriptive method of 3 basketball experts in the city of Cimahi; 3 experts are the expert in basketball. The instrument used was the ITB GDBB developed by Silvy (2019) consisting of top passing, bottom passing, top service, bottom service, chest passing, bounding passing, overhead passing, and leading ball (dribbling). This instrument consists of 76 items that cover 4 domains in basketball, namely chest pass, overhead pass, bound pass, and dribbling. The validity method used the construct validity of different power types. For the reliability method, it used the Kuder Ricardson (KR) and Objectivity analysis. The results of the construct validity analysis of a total of 76 items show that the score is ranged from 0.67 to 1.00. The construct validity value of 71 items in the basketball game is in the high category (= 1.00), 5 items are in the sufficient category, the relativity score is ranged from 0.75 to 0.98, and the objectivity score is ranged from 0.89 to 0.95. The conclusion is that this test instrument can be used as a standardized basic motion skill test for standardized large ball games for validity in basic motion skills in basketball games for grade VII junior high school students.
Given data
*The given mass of the rock is m = 2 kg
*The given potential energy is U_p = 407 J
(a)
The diagram of the energy bar graph is drawn below
(b)
If an object is at rest and has potential energy, once it starts to fall from its rest state then this potential energy is completely transferred to kinetic energy. This means that the magnitude of the kinetic energy is equal to the potential energy of the object.
The change in kinetic energy of the rock while falling to the ground is given as
(c)
The formula for the speed of the block is given as
![\begin{gathered} U_k=\frac{1}{2}mv^2 \\ v=\sqrt[]{\frac{2U_k}{m}} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20U_k%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%5C%5C%20v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2U_k%7D%7Bm%7D%7D%20%5Cend%7Bgathered%7D)
Substitute the known values in the above expression as
![\begin{gathered} v=\sqrt[]{\frac{2\times407}{2}} \\ =20.17\text{ m/s} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2%5Ctimes407%7D%7B2%7D%7D%20%5C%5C%20%3D20.17%5Ctext%7B%20m%2Fs%7D%20%5Cend%7Bgathered%7D)
Hence, the speed of the object is v = 20.17 m/s
