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4 years ago

14

What is the prerequisite for gravity to act?

1 answer:

MA_775_DIABLO [31]4 years ago

8 0

In order for gravity to act on a piece of mass, there has to be another piece of mass somewhere in the Universe. This is seldom an insurmountable requirement.

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The image represents what ?

nikitadnepr [17]

Answer:

what image. what i see is nothing. so i say it represents a failing grade. just kidding but i do not know what the image is so i can not answer the question .

Explanation:

6 0

4 years ago

HELP!! ILL GIVE BRAINLIEST As we've learned so far, the popular model of the solar system shifted over

Mademuasel [1]

Answer:

geotric earth simulator I think ya I have no idea

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3 years ago

An object acted on by a constant force F moves from point 1 to point 2 and back again. The work done by the force F in this roun

aksik [14]

Answer:

F is non-conservative.

If F were conservative no work would be done in moving back to the original point. F dot S = W if the net distance is zero the work done is zero for a conservative force

7 0

3 years ago

How much work<br> was done to<br> accelerate a 2.2<br> kg object from<br> rest to 26m/s?

Makovka662 [10]

Answer:

Explanation:

<em>work</em><em> </em><em>done</em><em> </em><em>=</em><em> </em><em>change</em><em> </em><em>in</em><em> </em><em>kinetic</em><em> </em><em>energy</em><em>,</em><em> </em><em>assuming</em><em> </em><em>there</em><em> </em><em>are</em><em> </em><em>no</em><em> </em><em>energy</em><em> </em><em>losses</em><em>.</em>

<em>work</em><em> </em><em>done</em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>×</em><em> </em><em>m</em><em> </em><em>×</em><em> </em><em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em><em>in</em><em> </em><em>v</em><em>^</em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>×</em><em> </em><em>2</em><em>.</em><em>2</em><em> </em><em>×</em><em> </em><em>(</em><em> </em><em>26</em><em>^</em><em>2</em><em> </em><em>-</em><em> </em><em>0</em><em>^</em><em>2</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>×</em><em> </em><em>2</em><em>.</em><em>2</em><em> </em><em>×</em><em> </em><em>676</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>743</em><em>.</em><em>6</em><em> </em><em>joules</em>

4 0

2 years ago

A merry-go-round makes one complete revolution in 5.3 s. A 48.5 kg child sits on the horizontal floor of the merry-go-round 2.7

Marianna [84]

Answer:183.94 N

Explanation:

Given

Time Period $T=5.3 s$

mass of child $m=48.5 kg$

Radius $r=2.7 m$

Velocity $v=\frac{2\pi \cdot r}{T}$

$v=\frac{2\pi \cdot 2.7}{5.3}$

$v=3.20 m/s$

Now Centripetal Force will be Balanced by Frictional Force

Centripetal Force $F_c=m\cdot \frac{v^2}{r}$

$F_c=48.5\cdot \frac{3.2^2}{2.7}$

$F_c=183.94 N$

therefore Friction Force is 183.94 N

4 0

3 years ago