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zlopas [31]
3 years ago
14

What is the prerequisite for gravity to act?

Physics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

In order for gravity to act on a piece of mass, there has to be another piece of mass somewhere in the Universe.  This is seldom an insurmountable requirement.

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A certain fm radio station broadcasts electromagnetic waves at a frequency of 125000 hertz. these radio waves travel at a speed
faltersainse [42]
Speed = frequency x wavelength
300,000,000 = 125000 x wavelength
wavelength = 125000/300,000,000 =4.16667x10^-4 meters
or 4.1667E-4 meters
4 0
3 years ago
A person wants to lose weight by "pumping iron". The person lifts an 80 kg weight 1 meter. How many times must this weight be li
statuscvo [17]

Answer:

37357 sec  

or 622 min

or 10.4 hrs

Explanation:

GIVEN DATA:

Lifting weight 80 kg

1 cal = 4184 J

from information given in question we have

one lb fat consist of 3500 calories = 3500 x 4184 J

= 14.644 x 10^6 J  

Energy burns in 1 lift = m g h

                                  = 80 x 9.8 x 1 = 784 J

lifts required = \frac{(14.644 x 10^6)}{784}

                      = 18679

from the question,

1 lift in 2 sec.

so, total time = 18679 x 2 = 37357 sec  

or 622 min

or 10.4 hrs

3 0
3 years ago
Which statement best describes the main idea of the poem
SSSSS [86.1K]

Explanation:

option D ) is correct the speaker explain a difficult decision he had to make

hi everyone comment

7 0
3 years ago
In a sound wave, the wavelength is equivalent to the distance from a region of high pressure to the region of mean
Alex
F!!! that is false.
4 0
3 years ago
The same ball is shot straight up a second time from the same gun, but this time the spring is compressed only half as far befor
Mekhanik [1.2K]

Answer:

The new height the ball will reach = (1/4) of the initial height it reached.

Explanation:

The energy stored in any spring material is given as (1/2)kx²

This energy is converted to potential energy, mgH, of the ball at its maximum height.

If the initial height reached is H

And the initial compression of the spring = x

So, mgH = (1/2)kx²

H = kx²/2mg

The new compression, x₁ = x/2

New energy of loaded spring = (1/2)kx₁²

And the new potential energy = mgH₁

mgH₁ = (1/2)kx₁²

But x₁ = x/2

mgH₁ = (1/2)k(x/2)² = kx²/8

H₁ = kx²/8mg = H/4 (provided all the other parameters stay constant)

6 0
3 years ago
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