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3 years ago

How can you find the net force if two forces act in opposite directions?

1 answer:

4 0

Then the magnitude of the net force is the difference between the two forces,
and its direction is the same as the direction of the greater one.

You might be interested in

How is it possible to get three precise but inaccurate measurements of the same volume of water

Lubov Fominskaja [6]

The inaccurate measurements must be similar to the other two measurements (ex; 590, 589, 599), but different from the actual volume of water. (Ex; the actual volume is let say.. 100, but you measured 50, 49, 40)

8 0

3 years ago

An irrigation canal has a rectangular cross section. At one point whare the canal is 16.0 m wide, and the water is 3.8 m deep, t

Irina-Kira [14]

Answer:

The depth of the water at this point is 0.938 m.

Explanation:

Given that,

At one point

Wide= 16.0 m

Deep = 3.8 m

Water flow = 2.8 cm/s

At a second point downstream

Width of canal = 16.5 m

Water flow = 11.0 cm/s

We need to calculate the depth

Using Bernoulli theorem

$A_{1}V_{1}=A_{2}V_{2}$

Put the value into the formula

$16.0\times3.8\times2.8=16.5\times x\times 11.0$

$x=\dfrac{16.0\times3.8\times2.8}{16.5\times11.0}$

$x=0.938\ m$

Hence, The depth of the water at this point is 0.938 m.

7 0

4 years ago

Does heating a metal wire increase or decrease its electrical resistance? Why?

Veseljchak [2.6K]

Heating any electrical conductor makes it's resistance INcrease.

4 0

4 years ago

What phase difference between two otherwise identical harmonic waves, moving in the same direction along a stretched string, wil

lora16 [44]

Answer:

$\theta=145$

Explanation:

The amplitude of he combined wave is:

$B=2Acos(\theta/2)\\$

A, is the amplitude from the identical harmonic waves

B, is the amplitude of the resultant wave

θ, is the phase, between the waves

The amplitude of the combined wave must be 0.6A:

$0.6A=2Acos(\theta/2)\\ cos(\theta/2)=0.3\\\theta/2=72.5\\\theta=145$

5 0

3 years ago

Consider a car travelling at 60 km/hr. If the radius of a tire is 25 cm, calculate the angular speed of a point on the outer edg

KengaRu [80]

Answer

given,

speed of car = 60 km/hr

= 60 x 0.278 m/s

= 16.68 m/s

radius of the tire = 25 cm = 0.25 m

time taken to stop = 6 s

average acceleration = ?

$\omega = \dfrac{v}{R}$

$\omega = \dfrac{16.68}{0.25}$

$\omega =66.72 rad/s$

average acceleration= $\dfrac{\Delta \omega}{\Delta t}$

= $\dfrac{66.72}{6}$

= 11.12 rad/s²

correct answer option D

b) length of sea saw = 10 m

mass of jack = 100 Kg

mass of Jill = 60 Kg

Let y be the distance from the Jack. To balance the seesaw moment on both side should balance each other about fulcrum

now,

100 x y = 5 x 60

y = 3 m

the correct answer is option B

4 0

3 years ago