Find the slope of the line that passes through (1, 2) and (10, 10).
2 answers:
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Answer:
Answers are in bold type
Step-by-step explanation:
f(x) =
The parabola opens up, so has a minimum at the vertex.
Let (h, k) be the vertex
h = -b/2a = - (-144)/2(1) = 57
k = 57^2 - 144(57) = 3249 - 6498 = -3249
Therefore, the vertex is (57, -3249)
The minimum value is -3249
The domain is the set of real numbers.
The range = {y | y ≥ -3249}
The function decreases when -∞ < x < 57 and increases when 57 > x > ∞
The x - intercepts: = 0
x(x - 114x) = 0
x = 0 or x = 114
x-intercepts are (0, 0) and (0, 114)
When x = 0, then we get the y-intercept. So, 0^2 - 114(0) = 0
y-intercept is (0, 0)
The parent function moves 4 units right and 3 units down. This is a translation by the vector.
According to the question,
Transformation maps onto
. Take f(x) =
and f(x+4)=
.
f(x) =
f(x+4)=
f(x+4) - 3= - 3
Analyze the function to see the translations. f(x-4) corresponds to a horizontal translation 4 units in the positive 'x' direction. f(x)-3 corresponds to a vertical translation 3 units in the negative 'y' direction.
Hence, the parent function moves 4 units right and 3 units down. This is a translation by the vector.
Learn more about parent function here
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