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2 years ago

Hhhhhhhhhhhheeeeeeeeeeeellllllllllllllllllpppppppppppppppp

Chemistry

2 answers:

shtirl [24]2 years ago

5 0

Answer:

They have good hearing

They have special adaptations that help them to be successful hunters

<h2>hope it helps</h2>

brainliest please

insens350 [35]2 years ago

4 0

Answer:

They have keen eyesight.

They have special adaptations that help them to be successful hunters.

Add-on:

i hope this helped at all. sorry if its incorrect.

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Enzymes are proteins that speed up chemical reactions in the body. How do they work?

KATRIN_1 [288]

They work by lowering the activation energy

3 0

2 years ago

Calculate the weighted average

padilas [110]

Of what?
Attach a link or pic

3 0

2 years ago

The second-order rate constants for the reaction of oxygen atoms witharomatic hydrocarbons have been measured (R. Atkinson and J

Pepsi [2]

Answer:

A = 1,13x10¹⁰

Ea = 16,7 kJ/mol

Explanation:

Using Arrhenius law:

ln k = -Ea/R × 1/T + ln(A)

You can graph ln rate constant in x vs 1/T in y to obtain slope: -Ea/R and intercept is ln(A).

Using the values you will obtain:

y = -2006,9 x +23,147

As R = 8,314472x10⁻³ kJ/molK:

-Ea/8,314472x10⁻³ kJ/molK = -2006,9 K⁻¹

Ea = 16,7 kJ/mol

Pre-exponential factor is:

ln A = 23,147

A = e^23,147

A = 1,13x10¹⁰

I hope it helps!

6 0

2 years ago

Which of the following is transferred due to a temperature difference?

quester [9]

Water can be turned to ice if to cold gas if to hot
ice can turn to water if to hot and stay the same if to cold
gas will turn to water if to hot and freeze to ice if to cold and the pattern keeps going like that.
hope this helps

8 0

2 years ago

A reaction of importance in the formation of smog is that between ozone and nitrogen monoxide described by O 3 ( g ) + NO ( g )

Aleksandr [31]

Answer:

(a) 7.11x10⁻⁴ M/s

(b) 2.56 mol.L⁻¹.h⁻¹

Explanation:

(a) The reaction is:

O₃(g) + NO(g) → O₂(g) + NO₂(g) (1)

The reaction rate of equation (1) is given by:

$rate = k*[O_{3}][NO]$ (2)

We have:

k: is the rate constant of reaction = 3.91x10⁶ M⁻¹.s⁻¹

[O₃]₀ = 2.35x10⁻⁶ M

[NO]₀ = 7.74x10⁻⁵ M

Hence, to find the inital reacion rate we will use equation (2):

$rate = k*[O_{3}]_{0}[NO]_{0} = 3.91 \cdot 10^{6} M^{-1}s^{-1}*2.35\cdot 10^{-6} M*7.74 \cdot 10^{-5} M = 7.11 \cdot 10^{-4} M/s$

Therefore, the inital reaction rate is 7.11x10⁻⁴ M/s

(b) The number of moles of NO₂(g) produced per hour per liter of air is:

t = 1 h

V = 1 L

$\frac{\Delta[NO_{2}]}{\Delta t} = rate$

$\frac{\Delta[NO_{2}]}{\Delta t} = 7.11 \cdot 10^{-4} M/s*\frac{3600 s}{1 h} = 2.56 mol.L^{-1}.h{-1}$

Hence, the number of moles of NO₂(g) produced per hour per liter of air is 2.56 mol.L⁻¹.h⁻¹

I hope it helps you!

5 0

2 years ago