Answer:
2022 L
Explanation:
Ideal gas laws will work for gas in the balloon
The general gas law is for a gas at two arbitrary states 1 and 2 is given by
(P₁ V₁)/T₁ = (P₂ V₂)/T₂
P₁ = 1.17 atm
V₁ = 200.0 L
T₁ = 20°C = 293.15 K
P₂ = 63 mmHg = 0.0829 atm
V₂ = ?
T₂ = 210 K
(1.17 × 200)/293.15 = (0.0829 × V₂)/210
V₂ = (210 × 1.17 × 200)/(293.15 × 0.0829)
V₂ = 2022 L
From the calculations, the heat of fusion of the substance is 0.73 kJ
<h3>What is is the heat of freezing?</h3>
The heat of freezing is the energy released when the substance is converted from liquid to solid.
Now we know that the molar mass of the substance is 82.9 g/mol hence the number of moles of the substance is; 13.3 g /82.9 g/mol = 0.16 moles
Now the heat of fusion shall be;
H = 4.60 kj/mol * 0.16 moles
H = 0.73 kJ
Learn more about freezing:brainly.com/question/3121416
#SPJ4
Answer:
![\boxed{\rm \text{[ClO$_{2}^{-}$] increases}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Crm%20%5Ctext%7B%5BClO%24_%7B2%7D%5E%7B-%7D%24%5D%20increases%7D%7D)
Explanation:
At the beginning, you have two reactions happening:

As you add KOH(aq), it does two things:
- It increases the volume of the solution.
- It reacts with the hydronium ions to form water.
A) The HCl is completely ionized. The Cl⁻ does not react, but it is diluted when the volume of the solution increases. [Cl⁻] decreases.
B) The KOH reacts with the H⁺ and removes it from the solution. [H⁺] decreases.
C) When all the H⁺ from the HCl has been neutralized, the KOH starts neutralizing the H⁺ from the HClO₂. According to Le Châtelier's Principle, more HClO₂ will dissociate to replace the decreased H⁺. [HClO₂] decreases.
D) As HClO₂ reacts, it forms ClO₂⁻. ![\boxed{\rm \textbf{[ClO$_{2}^{-}$] increases}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Crm%20%5Ctextbf%7B%5BClO%24_%7B2%7D%5E%7B-%7D%24%5D%20increases%7D%7D)