The theoretical yield of urea : = 227.4 kg
<h3>Further explanation</h3>
Given
Reaction
2NH3(aq)+CO2(aq)→CH4N2O(aq)+H2O(l)
128.9 kg of ammonia
211.4 kg of carbon dioxide
166.3 kg of urea.
Required
The theoretical yield of urea
Solution
mol Ammonia (MW=17 g/mol)
=128.9 : 17
= 7.58 kmol
mol CO₂(MW=44 g/mol) :
= 211.4 : 44
= 4.805 kmol
Mol : coefficient of reactant , NH₃ : CO₂ :
= 7.58/2 : 4.805/1
=3.79 : 4.805
Ammonia as limiting reactant(smaller ratio)
Mol urea based on mol Ammonia :
=1/2 x 7.58
=3.79 kmol
Mass urea :
=3.79 kmol x 60 g/mol
= 227.4 kg
Separate the components of a mixture.
Well there are 1,000 milligrams in 1 gram so 9.815 grams of sugar is equivalent to 9,815 milligrams of sugar. So a bar of milk chocolate contains 9,815 milligrams of sugar.
<h3>
Answer:</h3>
B. C7H16 + 11O2 → 7CO2 + 8H2O
<h3>
Explanation:</h3>
- In a balanced chemical equation, the number of atoms of each element is equal on both sides of the equation.
- In this case, the balanced chemical equation is;
C7H16 + 11O2 → 7CO2 + 8H2O
Because, it has 7 carbon atoms, 16 hydrogen atoms and 22 oxygen atoms on each side of the equation.
- When an equation is balanced it obeys the law of conservation of mass such that the mass of reactants will be equal to the mass of products.
A water molecule, because of its shape, is a polar molecule.
