Answer:
(a). The HB of this material is 217.8
(b). The diameter of an indentation is 1.45 mm.
Explanation:
Given that,
Diameter of Brinell hardness D= 10.0 m
Diameter of steel alloy d= 2.4 mm
Load = 1000 kg
(a). We need to calculate the HB of this material
Using formula of Brinell hardness
Put the value into the formula
(b). Given that,
Hardness = 300 HB
Load = 500 kg
We need to calculate the diameter of an indentation
Using formula of diameter
![d=\sqrt{D^2-[D-\dfrac{2P}{(HB)\pi D}]^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7BD%5E2-%5BD-%5Cdfrac%7B2P%7D%7B%28HB%29%5Cpi%20D%7D%5D%5E2%7D)
Put the value into the formula
![d=\sqrt{10^2-[10-\dfrac{2\times500}{300\pi\times10}]^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B10%5E2-%5B10-%5Cdfrac%7B2%5Ctimes500%7D%7B300%5Cpi%5Ctimes10%7D%5D%5E2%7D)
Hence,(a). The HB of this material is 217.8
(b). The diameter of an indentation is 1.45 mm.
A car is traveling due north at 23.6 m>s.
Find the velocity of the car after 7.10 s if its
acceleration is
The acceleration is known to be: a(t) = 1.7 m/s2.
We must integrate over time to obtain the velocity function, and the results are:
v(t) = (1.7m/s^2)
*t + v0
If we suppose that we begin at 23.6 m/s, then the initial velocity is: v0 = 23.6 m/s, where v0 is the beginning velocity.
The velocity formula is then: v(t) = (1.7m/s2).
*t + 23.6 m/s
We now seek to determine the value of t such that v(t) = 27.8 m/s.
Consequently, v(t) = 27.8 m/s = (1.7 m/s2)
*t + 23.6 m/s = (1.7 m/s2) 27.8 m/s - 23.6 m/s
t = 2.5 seconds when *t 4.2 m/s = (1.7 m/s/2)
At such acceleration, 2.5 seconds are required.
To learn more about acceleration Visit :
brainly.com/question/19599982
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Answer: I hope this helps you
Explanation:
