Answer:
The face of the claw on the claw hammer is usually a smooth curve so as to improve the ease with which nails are removed when removing nails because as the nail held between the V shaped split claw is being pulled out from the wood, it slides more and more towards cheek, reducing the distance of the nail from the cheek which is the fulcrum, thereby increasing the mechanical advantage because the location of the hand on the grip remains unchanged
Explanation:
Answer:
Explanation:
The turbine is modelled after the First Law of Thermodynamics:
The rate of heat transfer between the turbine and its surroundings is:
The specific enthalpies at inlet and outlet are, respectively:
The required output is:
![\dot Q_{out} = \left(8\,\frac{kg}{s} \right)\cdot \left\{3076.41\,\frac{kJ}{kg}-2675.0\,\frac{kJ}{kg}+\frac{1}{2}\cdot \left[\left(65\,\frac{m}{s} \right)^{2}-\left(42\,\frac{m}{s} \right)^{2}\right] + \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4\,m) \right\} - 8000\,kW](https://tex.z-dn.net/?f=%5Cdot%20Q_%7Bout%7D%20%3D%20%5Cleft%288%5C%2C%5Cfrac%7Bkg%7D%7Bs%7D%20%5Cright%29%5Ccdot%20%5Cleft%5C%7B3076.41%5C%2C%5Cfrac%7BkJ%7D%7Bkg%7D-2675.0%5C%2C%5Cfrac%7BkJ%7D%7Bkg%7D%2B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5Cleft%5B%5Cleft%2865%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%29%5E%7B2%7D-%5Cleft%2842%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%29%5E%7B2%7D%5Cright%5D%20%2B%20%5Cleft%289.807%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%5Cright%29%5Ccdot%20%284%5C%2Cm%29%20%5Cright%5C%7D%20-%208000%5C%2CkW)
Answer:
a) The flow has three dimensions (3 coordinates).
b) ∇V = 0 it is a incompressible flow.
c) ap = (16/3) i + (32/3) j + (16/3) k
Explanation:
Given
V = xy² i − (1/3) y³ j + xy k
a) The flow has three dimensions (3 coordinates).
b) ∇V = 0
then
∇V = ∂(xy²)/∂x + ∂(− (1/3) y³)/∂y + ∂(xy)/∂z
⇒ ∇V = y² - y² + 0 = 0 it is a incompressible flow.
c) ap = xy²*∂(V)/∂x − (1/3) y³*∂(V)/∂y + xy*∂(V)/∂z
⇒ ap = xy²*(y² i + y k) - (1/3) y³*(2xy i − y² j + x k) + xy*(0)
⇒ ap = (xy⁴ - (2/3) xy⁴) i + (1/3) y⁵ j + (xy³ - (1/3) xy³) k
⇒ ap = (1/3) xy⁴ i + (1/3) y⁵ j + (2/3) xy³ k
At point (1, 2, 3)
⇒ ap = (1/3) (1*2⁴) i + (1/3) (2)⁵ j + (2/3) (1*2³) k
⇒ ap = (16/3) i + (32/3) j + (16/3) k
Answer:
the rate of heat loss from the steam turbine is Q = 200 kW
Explanation:
From the first law of thermodynamics applied to open systems
Q-W₀ = F*(ΔH + ΔK + ΔV)
where
Q= heat loss
W₀= power generated by the turbine
F= mass flow
ΔH = enthalpy change
ΔK = kinetic energy change
ΔV = potencial energy change
If we neglect the changes in potential and kinetic energy compared with the change in enthalpy , then
Q-W₀ = F*ΔH
Q = F*ΔH+ W₀
replacing values
Q = F*ΔH+ W₀ = 420 kg/min * (-600 kJ/kg) * 1 min/60 s * 1 MW/1000 kW + 4 MW = -0.2 MW = -200 kW (negative sign comes from outflow of energy)
Answer:
A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.
Explanation:
